在我的代码中,这个错误一直在左、右和中间出现。真烦人。到现在为止,我已经把它们都修好了,但我似乎修不好这个。
Traceback (most recent call last):
File "C:\Users\Home\Desktop\da.py", line 31, in <module>
if (number > 1):
TypeError: '>' not supported between instances of 'str' and 'int'
代码本身:
from tkinter import *
from tkinter import ttk
import tkinter as tk
def add_text():
global number
number = num_textbox.get()
print(number)
root = Tk()
root.title("Number Cent Divider")
root.geometry("330x85")
num_col_mat = Label(root, text="Your number:")
num_col_mat.pack()
num_textbox = Entry(root, bd=1)
num_textbox.pack()
enter_button = Button(root, text="Enter", command=add_text)
enter_button.pack()
root.mainloop()
if (number[-1] == 5 or number[-1] == 0):
number / 5
int(number)
if (number > 1):
answer = "\number 5 cent coins"
str(number)
popup()
else:
answer = "\number 5 cent coin"
str(number)
popup()
else:
int(number)
if (number > 1):
answer = "\number 1 cent coins"
str(number)
popup()
else:
answer = "\number 1 cent coin"
str(number)
popup()
def popup():
popup = tk.Tk()
popup.wm_title("answer")
answer = Label(popup, text=answer)
answer.pack
B1 = ttk.Button(popup, text="Ok", command=popup.destroy)
B1.pack()
任何帮助将不胜感激,因为这个错误不想得到修复。
number
是一个str
,因此首先需要将其转换为数字。E、 g.:在一行上单独写
int(number)
不会有任何作用。。。它只返回一个数字,然后忽略它。如果要将结果存储在number
变量中,可以使用number = int(number)
。考虑使用
number = int(num_textbox.get())
来获得前面的转换。(但请注意,如果该文本框的内容不是有效数字,则会出现异常。)相关问题 更多 >
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