列表是另一个列表的子集

Question

在Python中，给定两个对列表：

listA = [ [1,20], [3,19], [37,11], [21,17] ]
listB = [ [1,20], [21,17] ]

如果listB是listA的子集，如何高效地编写返回True的python函数？oh和[1,20]对等于[20,1]

Answer 1

为了提供另一种选择，也许使用tuple和set更有效：

>>> set(map(tuple,listB)) <= set(map(tuple,listA))
True

Answer 2

使用frozenset。

>>> listA = [ [1,20], [3,19], [37,11], [21,17] ]
>>> listB = [ [1,20], [21,17] ]

>>> setA = frozenset([frozenset(element) for element in listA])
>>> setB = frozenset([frozenset(element) for element in listB])

>>> setA
frozenset([frozenset([17, 21]), frozenset([1, 20]), frozenset([11, 37]), frozens
et([19, 3])])
>>> setB
frozenset([frozenset([17, 21]), frozenset([1, 20])])

>>> setB <= setA
True