更换和储存

Question

那么，我得到的是：

def getSentence():

  sentence = input("What is your sentence? ").upper()

  if sentence == "":
    print("You haven't entered a sentence. Please re-enter a sentence.")
    getSentence()
  elif sentence.isdigit():
    print("You have entered numbers. Please re-enter a sentence.")
    getSentence()
  else:
    import string
    for c in string.punctuation:
      sentence = sentence.replace(c,"")
      return sentence

def list(sentence):

  words = []
  for word in sentence.split():
    if not word in words:
      words.append(word)
    print(words)

def replace(words,sentence):
  position = []
  for word in sentence:
    if word == words[word]:
      position.append(i+1)
      print(position)

sentence = getSentence()
list = list(sentence)
replace = replace(words,sentence)

我只想做到这一点，我的全部意图是把这个句子，分成几个单词，把每个单词变成一个数字

words = ["Hello","world","world","said","hello"]

使每个单词都有一个数字：

所以，假设“hello”的值为1，句子将是“1 world said 1”

如果世界是2，那就是“12说1”
最后，如果“said”是3，那就是“12”

如果有任何帮助，我将非常感谢，然后我将开发此代码，以便使用file.write()和file.read()等将句子等存储到文件中

谢谢

Answer 1

如果你只想知道每个单词的位置，你可以做到

positions = map(words.index,words)

另外，不要对变量或函数使用内置函数名。也不要像调用函数一样调用变量（replace = replace(...)），函数是对象

编辑：在Python3中，必须将映射返回的迭代器转换为列表

positions = list(map(words.index, words))

或者使用理解列表

positions = [words.index(w) for w in words]

Answer 2

另一个想法（尽管不认为它比其他的好），使用字典：

dictionary = dict()
for word in words:
    if word not in dictionary:
        dictionary[word] = len(dictionary)+1

另外，在代码中，当您在“getSentence”中调用“getSentence”时，应该返回其返回值：

if sentence == "":
    print("You haven't entered a sentence. Please re-enter a sentence.")
    return getSentence()
elif sentence.isdigit():
    print("You have entered numbers. Please re-enter a sentence.")
    return getSentence()
else:
    ...

Answer 3

单词变成数字的顺序重要吗？Hello和hello是两个词还是一个词？为什么不这样做：

import string

sentence = input()  # user input here
sentence.translate(str.maketrans('', '', string.punctuation))
# strip out punctuation

replacements = {ch: str(idx) for idx, ch in enumerate(set(sentence.split()))}
# builds {"hello": 0, "world": 1, "said": 2} or etc

result = ' '.join(replacements.get(word, word) for word in sentence.split())
# join back with the replacements