为什么我的代码找不到数组中存在的某个字符串？

Question

我正在写一个程序，这是一个小文本冒险游戏排序，但我似乎遇到了一些问题，我的代码。我是一个比较新的编程作为一个整体，所以如果你能解释你的答案深入将是很大的帮助。你知道吗

代码如下：

#text_adventure_game.py
#python_ver == 3.5

verbs = ["get",
         "put",
         "drop",
         "use",
         "enter",
         "leave",
         "walk",
         "search",
         "attack",
         "defend"]

nouns = ["journal",
         "magnifier",
         "glasses",
         "knife",
         "kite",
         "table",
         "chair",
         "key"]

inventory = ""

user_input = input("What would you like to do?\n")

#checking if there are a set of two instructions
if(len(user_input.split())==2):
    counter = 0
    for token in user_input.split():
        print(token)
        print(counter)
        if(counter==0):
            if(token not in verbs):
                print("I did not understand the verb entered.")
                #removing square brackets and single quote marks from the array
                print("Please use:", ", ".join(verbs))
                counter = counter + 1
            elif(token in verbs):
                print("Recognized verb entered.")
                counter = counter + 1
        if(counter==1):
            if(token not in nouns):
                print("I did not understand the noun entered.")
                print("Please use:", ", ".join(nouns))
                counter = counter + 1
            elif(token in nouns):
                print("Recognized verb entered.")
                counter = counter + 1

我的问题是它无法识别我在“nomnes”数组中输入的名词。你知道吗

它是这样编译的：

>>> 
What would you like to do?
get journal
get
0
Recognized verb entered.
I did not understand the noun entered.
Please use: journal, magnifier, glasses, knife, kite, table, chair, key
journal
2

如果有更有效的方法来做这样的事情，那也会有帮助。你知道吗

谢谢。你知道吗

Answer 1

不需要for循环和计数器。您可以更简单地执行以下操作：

verbs = ["get",
         "put",
         "drop",
         "use",
         "enter",
         "leave",
         "walk",
         "search",
         "attack",
         "defend"]

nouns = ["journal",
         "magnifier",
         "glasses",
         "knife",
         "kite",
         "table",
         "chair",
         "key"]

inventory = ""

user_input = input("What would you like to do?\n")

#checking if there are a set of two instructions
action, obj = user_input.split()

if(action not in verbs):
    print("I did not understand the verb entered.")
    print("Please use:", ", ".join(verbs))
else:
    print("Recognized verb entered.")

    if(obj not in nouns):
        print("I did not understand the noun entered.")
        print("Please use:", ", ".join(nouns))
    else:
        print("Recognized noun entered.")

如果您想在失败后重复，可以将代码放在while块下。你知道吗

不管怎样，原始代码中的问题是，如果第一个动词正确，则必须插入continue：

verbs = ["get",
         "put",
         "drop",
         "use",
         "enter",
         "leave",
         "walk",
         "search",
         "attack",
         "defend"]

nouns = ["journal",
         "magnifier",
         "glasses",
         "knife",
         "kite",
         "table",
         "chair",
         "key"]

inventory = ""

user_input = input("What would you like to do?\n")

#checking if there are a set of two instructions
if(len(user_input.split())==2):
    counter = 0
    for token in user_input.split():
        print("1", token)
        print(counter)
        if(counter==0):
            if(token not in verbs):
                print("I did not understand the verb entered.")
                #removing square brackets and single quote marks from the array
                print("Please use:", ", ".join(verbs))
                counter = counter + 1
            elif(token in verbs):
                print("Recognized verb entered.")
                counter = counter + 1
                continue
        if(counter==1):
            if(token not in nouns):
                print("I did not understand the noun entered.")
                print("Please use:", ", ".join(nouns))
                counter = counter + 1
            elif(token in nouns):
                print("Recognized verb entered.")
                counter = counter + 1

Answer 2

当您找到动词时，您将递增计数器，因此在递增标记之前执行if（counter==1）行（当counter==1块执行时，标记仍然包含“get”）。你知道吗

最简单的解决办法就是

if(counter==1):

变成elif：

elif(counter==1):

或者，如果您希望友好而明确，您可以在每次成功处理令牌时添加一个“continue”，循环将进入下一次迭代，而不再处理循环体：

if(counter==0):
    if(token in verbs):
        print("Recognized verb entered.")            
    else
        print("I did not understand the verb entered.")
        #removing square brackets and single quote marks from the array
        print("Please use:", ", ".join(verbs))

    counter = counter + 1
    continue

（注意，我还更改了if/elif测试，因为您正在测试两个互斥的布尔条件-“in”和“not in”。）

希望有帮助。你知道吗

Answer 3

问题是在“if（counter==0）”中增加计数器变量 从0到1。因为后面还有另一个if语句（“if（counter==1）：”），两个if语句都将在同一个迭代中执行，这意味着输入“get key”时，您将检查“get”是否在动词中，也检查“get”是否在名词中。我建议把第二个if改成这样的elif：

verbs = ["get",
         "put",
         "drop",
         "use",
         "enter",
         "leave",
         "walk",
         "search",
         "attack",
         "defend"]

nouns = ["journal",
         "magnifier",
         "glasses",
         "knife",
         "kite",
         "table",
         "chair",
         "key"]

inventory = ""

user_input = input("What would you like to do?\n")

#checking if there are a set of two instructions
if(len(user_input.split())==2):
    counter = 0
    for token in user_input.split():
        print(token)
        print(counter)
        if(counter==0):
            if(token not in verbs):
                print("I did not understand the verb entered.")
                #removing square brackets and single quote marks from the array
                print("Please use:", ", ".join(verbs))
                counter += 1
            else: #this can be simplified as an else since the booleans you check are mutually exclusive
                print("Recognized verb entered.")
                counter += 1
        elif(counter==1): #this now only executes if counter isn't 1 to make sure it only triggers on the second word in the array
            if(token not in nouns):
                print("I did not understand the noun entered.")
                print("Please use:", ", ".join(nouns))
                counter += 1
            else:
                print("Recognized noun entered.")
                counter += 1