<p><strong>这可能不会直接回答这个问题,但有助于澄清相关概念。</strong></p>
<p>如果在函数中创建嵌套对象并返回它,则该对象将继续存在。即使函数结束,它也不会超出范围。</p>
<p><strong>示例代码</strong></p>
<pre><code>class Some_Class (object):
prop_x = None
def __init__(self, prop_x ):
self.prop_x = prop_x
def __repr__(self):
return "prop_x = "+repr (self.prop_x)
def fx ():
dict_x = { "k1" : "v1" }
print hex ( id (dict_x) )
obj1 = Some_Class ( prop_x = dict_x )
print hex ( id (obj1.prop_x) )
print "obj1 is "+repr( obj1 )
return obj1
recv_obj = fx ()
print "recv_obj is "+repr( recv_obj )
print hex ( id (recv_obj.prop_x) )
</code></pre>
<p><strong>输出</strong></p>
<pre><code>0xdfaae0
0xdfaae0
obj1 is prop_x = {'k1': 'v1'}
recv_obj is prop_x = {'k1': 'v1'}
0xdfaae0
</code></pre>
<p>dict <code>dict_x</code>被分配给类对象<code>obj1</code>的<code>prop_x</code>变量。dict不会在内存中再次创建,但会发生<code>soft copy</code>。<code>prop_x</code>指向<code>dict_x</code>的内存位置。</p>
<p>当您在函数末尾返回对象<code>obj1</code>时,<code>dict_x</code>超出了范围,但它使用的内存地址<code>0xdfaae0</code>仍由返回对象<code>prop_x</code>中的<code>recv_obj</code>指向。因此,dict值<code>{ "k1" : "v1" }</code>保存在内存中。</p>