在python中从奇怪的列表传递值

Question

如果单词匹配，我想将内部列表的第一个值（数字）传递给dict

缓冲区：

 ['from', 
'landi', 
'stsci', 
'edu', 
'four'...]

列表1：

[('focus', [-1, -2]), 
('four', [-3.3, -1.04]),
...)]

for key in docs_A_rec:
    for word, number_1,number_2  in list_1:
       if word in buffer:
           docs_A_rec[key]['idf'][word] = list_1[word][number_1]

我得到这个错误：

ValueError: need more than 2 values to unpack

谢谢你。你知道吗

Answer 1

>>> buffer = ['from', 'landi', 'stsci', 'edu', 'four']
>>> list_1 = [('focus', [-1, -2]), ('four', [-3.3, -1.04])]
>>>
>>> for key1 in buffer:
...   for key2 in list_1:
...     if (key1 != key2[0]):
...       continue;
...     print key1
...     print key2[1][0]
...
four
-3.3
>>>

所以，下面这些就足够了

for key1 in buffer:
  for key2 in list_1:
    if (key1 == key2[0]):
      list_1[key1][key2[1][0]]

Answer 2

应该是这样的：

[('focus', [-1, -2]), 
('four', [-3.3, -1.04]),
...)]

for key in docs_A_rec:
    for word, (number_1,number_2)  in list_1:
       if word in buffer:
           docs_A_rec[key]['idf'][word] = list_1[word][number_1]

Answer 3

第二个循环中有一个bug，请按以下方式修复它：

for key in docs_A_rec:
    for word, (number_1,number_2)  in list_1:
       if word in buffer:
           docs_A_rec[key]['idf'][word] = templist[word][number_1]

希望有帮助！你知道吗