我的简单的python游戏不起作用请找出我的错误

Question

from random import randint
import sys
l2= ["Rock", "Paper", "Scissors"]

computer = l2[randint(0,2)]
wins = 0
losses = 0

player = False

while player == False:
    player = input("Rock," "Paper," "Scissors")
    if player == computer:
        print("Tie")    
    elif player == "Rock":
        if computer == "Paper":
            print("You lose")
        else:
            print("You win Congrats")
    elif player == "Paper":
        if computer == "Scissors":
            print("You lose")
        else:
            print("You win Congrats")    
    elif player == "Scissors":
        if computer == "Rock":
            print("Try again")
        else:
            print("You won")
    elif player == "Rock":
        if computer == "Scissors":
            print("You won")
    elif player == "Paper":
        if computer == "Rock":
            print("You won")
    elif player == "Scissors":
        if computer == "Paper":
            print("You won")
    else:
        print("That is not a valid play Game Over for you")
    player = False
    computer = l2[randint(0,2)] 

我的代码由于某种原因无法运行，它只在终端上显示else语句。我不知道我做错了什么。请帮助我，初学者在这里学习python和做一些简单的项目开始。你知道吗

Answer 1

看看你的代码，大约一半的if-else案例不起作用。你的代码怎么了？代码正在运行。你可以消除一半的elif案例，因为它们永远不会执行。If和elif是连续的。如果您仍然认为您的代码不起作用，请逐个缓慢地进行调试。如中所示，将计算机设置为常量并测试所有情况。你知道吗

我复制粘贴了你的代码，它工作得很好，至少表面上的功能。删除不必要的elif：

from random import randint
import sys
l2= ["Rock", "Paper", "Scissors"]

computer = l2[randint(0,2)] 

wins = 0
losses = 0

player = False

while player == False:
    player = input("Rock,Paper,Scissors: ") #clean up the query
    print("Computer had ",computer) #You use this to debug to make sure the logic is working. 
    print("You entered ",player) # another print to make it look nicer
    if player == computer:
        print("Tie")    
    elif player == "Rock":
        if computer == "Paper":
            print("You lose")
        else:
            print("You win Congrats")
    elif player == "Paper":
        if computer == "Scissors":
            print("You lose")
        else:
            print("You win Congrats")    
    elif player == "Scissors":
        if computer == "Rock":
            print("Try again")
        else:
            print("You won")
    else:
        print("That is not a valid play Game Over for you")
    player = False
    computer = l2[randint(0,2)] 

逻辑运作得很好。祝你在游戏中添加其他功能好运。你知道吗

我建议尝试使用upper（）来减少打字错误造成的失败，也可以使用exit string命令。对于您似乎想要添加的赢/输功能，只需做一个添加到赢/输号码的标志。你也可以添加其他“命令”到你的游戏与更多的如果否则的情况。祝你好运。你知道吗

Answer 2

首先，不应该在同一个问题上添加Python2.x和Python3.x标记。为了简单起见，我在3.x上尝试了你的代码，它部分工作。 第二，描述你的问题。不要只写“因为某些原因不会跑”。 第三，描述你想要达到的目标。我将为你举个例子。你知道吗

你的游戏是这样运作的：

1. 确定计算机的功能

2. 询问玩家做什么（部分工作）

3. 比较播放器和计算机操作并打印结果（不起作用）

4. 从1开始（不起作用）

第一个问题是while循环，您应该这样做：

while True:

为什么？你想要一个永无止境的循环只有当玩家输入了一个错误的动作，然后你想要强制循环结束，你用一个“break”语句来完成。你知道吗

你的第二个问题是，你使用了太多的if-else构造，你不需要那么多来处理所有的情况。下面是我的Python 3代码：

from random import randint
import sys

l2 = ["Rock", "Paper", "Scissors"]

computer = None
player = None
wins = 0
losses = 0
ties = 0

def win():
    global wins
    wins += 1 
    print("You win")

def loss():
    global losses
    losses += 1
    print("You lose")

def tie():
    global ties
    ties += 1
    print("Game ended with a tie")

while True:
    # determine computer action
    computer = l2[randint(0,2)]
    player = input("Choose your action. Possible values are Rock, Paper or Scissors.\n")
    if player not in l2:
        print("Invalid choice, game will end now.")
        print("You won {0} games and lost {1} games, {2} game(s) ended with a tie.".format(wins, losses, ties))
        # ending the loop
        break
    if player == computer:
        tie()
    elif player == "Rock":
        if computer == "Paper":
            win()
        else:
            loss()
    elif player == "Paper":
        if computer == "Scissors":
            loss()
        else:
            win()   
    elif player == "Scissors":
        if computer == "Rock":
            loss()
        else:
            win()

如果你有任何问题，问我。你知道吗

Edit：您还应该考虑将函数和主循环移动到它自己的（game）类中，这样就不需要使用丑陋的“global”语句来访问变量。你知道吗

Answer 3

我还有一个石头布剪刀的游戏

以下是一些工作代码：

import random
computer = random.choice(["rock", "paper", "scissors"])
player = input("What do you choose?")
player = player.lower()
print(f"Computer picks {computer} and Player picks {player}")
if computer == player:
    print('Game is a tie, play again!')
if player == "paper":
  if computer == "rock":
    print('Player wins!')
  if computer == "scissors":
    print('Computer wins!')
if player == "rock":
  if computer == "paper":
    print('Computer wins!')
  if computer == "scissors":
    print('Player wins!')
if player == "scissors":
  if computer == "rock":
    print('Computer wins!')
  if computer == "paper":
    print('Player wins!')