使用regex从html文本中获取两个或更多连续的大写单词

2024-04-26 11:35:59 发布

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我试图提取两个或更多单词的所有序列，每个单词的第一个字母都大写。我原以为这个'[A-Z][a-z]+(?=\s[A-Z])(?:\s[A-Z][a-z]+)+'可以用，但它添加了一些我无法解释的字符。你知道吗

完整代码如下：

import re
import unittest
from bs4 import BeautifulSoup
html_page = """
<html>
<body>
<table>
<tr class=tb1><td>Lorem Ipsum dolor Sit amet</td></tr>
<tr class=tb1><td>Consectetuer adipiscing elit</td></tr>
<tr><td>Aliquam Tincidunt mauris eu Risus</td></tr>
<tr><td>Vestibulum Auctor Dapibus neque</td></tr>
</table>
</body>
</html>
"""

soup = BeautifulSoup(html_page)
text = soup.get_text()

def get_sequences(page):
    ex = re.compile('[A-Z][a-z]+(?=\s[A-Z])(?:\s[A-Z][a-z]+)+')
    sequences = re.findall(ex, page)
    return sequences

print get_sequences(text)

期望的结果应该是 ['Lorem Ipsum', 'Aliquam Tincidunt', 'Vestibulum Auctor Dapibus']

但是我却得到了 [u'Lorem Ipsum', u'Aliquam Tincidunt', u' Risus\nVestibulum Auctor Dapibus']


Tags： textimportregethtmlpagetrtd
3条回答
网友
1楼 · 编辑于 2024-04-26 11:35:59

这种做法是正确的，但没有针对性。您要查找的是一行中两个或多个连续的大写单词。所以，应该在文本中的行上运行regex。这样做的诀窍：

def get_sequences(page):
    ex = re.compile('[A-Z][a-z]+(?=\s[A-Z])(?:\s[A-Z][a-z]+)+')
    sequences = []
    for x in page.splitlines():
        sequences.append(re.findall(ex, x))
    sequences = sum(sequences,[])
    return sequences
网友
2楼 · 编辑于 2024-04-26 11:35:59

Python代码：

# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility

import re

regex = r"[A-Z][a-z]+\s+[A-Z][a-z]+"

test_str = ("<html>\n"
    "<body>\n"
    "<table>\n"
    "<tr class=tb1><td>Lorem Ipsum dolor Sit amet</td></tr>\n"
    "<tr class=tb1><td>Consectetuer adipiscing elit</td></tr>\n"
    "<tr><td>Aliquam Tincidunt mauris eu Risus</td></tr>\n"
    "<tr><td>Vestibulum Auctor Dapibus neque</td></tr>\n"
    "</table>\n"
    "</body>\n"
    "</html>\n"
    "\"\"\"")

matches = re.finditer(regex, test_str, re.MULTILINE)

for matchNum, match in enumerate(matches):
    matchNum = matchNum + 1

    print (match.group())

# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.

结果：

Lorem Ipsum
Aliquam Tincidunt
Vestibulum Auctor

见：http://ideone.com/iQev8D

网友
3楼 · 编辑于 2024-04-26 11:35:59

您可以使用以下选项：

((?:[A-Z][a-z]+\s*){2,})

https://regex101.com/r/EeS7F5/1示例

您还可以修改当前的regex并去掉lookahead

视图https://regex101.com/r/vViHXm/1

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