我正在尝试构建一个python kivy应用程序,它可以创建弹出窗口并根据用户的输入返回结果。Kivy应用程序应该一直运行,直到弹出窗口被关闭。我可以创建第一个应用程序,并得到正确的弹出结果,但我得到一个错误后,尝试创建第二个应用程序。我不能在Kivy中创建多个(非同时)应用程序吗?你知道吗
from kivy.app import App
from kivy.uix.popup import Popup
from kivy.uix.floatlayout import FloatLayout
from kivy.core.window import Window
from kivy.lang.builder import Builder
Builder.load_string("""
<PopupYesNo>:
Label:
id: label
text: "Hello"
pos_hint: {'center_x':0.5, 'center_y':0.65}
Button:
text: "Yes"
size_hint: 0.3, 0.2
pos_hint: {'center_x':0.25, 'top':0.25}
on_release: root.dismiss('Yes')
Button:
text: "No"
size_hint: 0.3, 0.2
pos_hint: {'center_x':0.75, 'top':0.25}
on_release: root.dismiss('No')
""")
class MyPopupApp(App):
def __init__(self, popup_text):
super(MyPopupApp, self).__init__()
self.popup_text = popup_text
self.result = ''
def build(self):
Window.size = 300, 200
Window.borderless = True
self.title = "Input"
popup = PopupYesNo()
popup.set_text(self.popup_text)
popup = Popup(title='Input', size=(300, 200), size_hint=(None, None), content=popup)
return popup
class PopupYesNo(FloatLayout):
def set_text(self, text):
self.ids['label'].text = text
def dismiss(self, value):
app = App.get_running_app()
app.result = value
app.stop()
if __name__ == '__main__':
app = MyPopupApp("Are you reading this?")
app.run()
print('First popup result: '+ app.result)
app = MyPopupApp("Choose yes or no")
app.run()
print('First popup result: '+ app.result)
我得到的错误::(
File "C:\Python27\lib\site-packages\kivy\app.py", line 855, in run
runTouchApp()
File "C:\Python27\lib\site-packages\kivy\base.py", line 506, in runTouchApp
stopTouchApp()
File "C:\Python27\lib\site-packages\kivy\base.py", line 521, in stopTouchApp
EventLoop.close()
File "C:\Python27\lib\site-packages\kivy\base.py", line 172, in close
self.stop()
File "C:\Python27\lib\site-packages\kivy\base.py", line 184, in stop
provider.stop()
File "C:\Python27\lib\site-packages\kivy\input\providers\wm_pen.py", line 111, in stop
SetWindowLong_WndProc_wrapper(self.hwnd, self.old_windProc)
File "C:\Python27\lib\site-packages\kivy\input\providers\wm_common.py", line 122, in _closure
oldAddr = func(hWnd, GWL_WNDPROC, cast(wndProc, c_void_p).value)
ctypes.ArgumentError: argument 3: <type 'exceptions.TypeError'>: wrong type
目前没有回答
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