我的sql中有一个大型数据集,例如:
("Successfully confirmed payment - {'PAYMENTINFO_0_TRANSACTIONTYPE': ['expresscheckout'], 'ACK': ['Success'], 'PAYMENTINFO_0_PAYMENTTYPE': ['instant'], 'PAYMENTINFO_0_RECEIPTID': ['1037-5147-8706-9322'], 'PAYMENTINFO_0_REASONCODE': ['None'], 'SHIPPINGOPTIONISDEFAULT': ['false'], 'INSURANCEOPTIONSELECTED': ['false'], 'CORRELATIONID': ['1917b2c0e5a51'], 'PAYMENTINFO_0_TAXAMT': ['0.00'], 'PAYMENTINFO_0_TRANSACTIONID': ['3U4531424V959583R'], 'PAYMENTINFO_0_ACK': ['Success'], 'PAYMENTINFO_0_PENDINGREASON': ['authorization'], 'PAYMENTINFO_0_AMT': ['245.40'], 'PAYMENTINFO_0_PROTECTIONELIGIBILITY': ['Eligible'], 'PAYMENTINFO_0_ERRORCODE': ['0'], 'TOKEN': ['EC-82295469MY6979044'], 'VERSION': ['95.0'], 'SUCCESSPAGEREDIRECTREQUESTED': ['true'], 'BUILD': ['7507921'], 'PAYMENTINFO_0_CURRENCYCODE': ['GBP'], 'TIMESTAMP': ['2013-08-29T09:15:59Z'], 'PAYMENTINFO_0_SECUREMERCHANTACCOUNTID': ['XFQALBN3EBE8S'], 'PAYMENTINFO_0_PROTECTIONELIGIBILITYTYPE': ['ItemNotReceivedEligible,UnauthorizedPaymentEligible'], 'PAYMENTINFO_0_ORDERTIME': ['2013-08-29T09:15:59Z'], 'PAYMENTINFO_0_PAYMENTSTATUS': ['Pending']}", 1L, datetime.datetime(2013, 8, 29, 11, 15, 59))
我使用下面的正则表达式从花括号中的第一个项目列表中提取数据
paypal_meta_re = re.compile(r"""\{(.*)\}""").findall
这和预期的一样,但是当我试图从字典值中删除方括号时,我得到了一个错误。你知道吗
这是我的密码:
paypal_meta = get_paypal(order_id)
paypal_msg_re = paypal_meta_re(paypal_meta[0])
print type(paypal_msg_re), len(paypal_msg_re)
paypal_str = ''.join(map(str, paypal_msg_re))
print paypal_str, type(paypal_str)
paypal = ast.literal_eval(paypal_str)
paypal_dict = {}
for k, v in paypal.items():
paypal_dict[k] = str(v[0])
if paypal_dict:
namespace['payment_gateway'] = { 'paypal' : paypal_dict}
以下是回溯:
Traceback (most recent call last):
File "users.py", line 383, in <module>
orders = get_orders(user_id, mongo_user_id, address_book_list)
File "users.py", line 290, in get_orders
paypal = ast.literal_eval(paypal_str)
File "/usr/local/Cellar/python/2.7.2/lib/python2.7/ast.py", line 49, in literal_eval
node_or_string = parse(node_or_string, mode='eval')
File "/usr/local/Cellar/python/2.7.2/lib/python2.7/ast.py", line 37, in parse
return compile(source, filename, mode, PyCF_ONLY_AST)
File "<unknown>", line 1
'PAYMENTINFO_0_TRANSACTIONTYPE': ['expresscheckout'], 'ACK': ['Success'], 'PAYMENTINFO_0_PAYMENTTYPE': ['instant'], 'PAYMENTINFO_0_RECEIPTID': ['2954-8480-1689-8177'], 'PAYMENTINFO_0_REASONCODE': ['None'], 'SHIPPINGOPTIONISDEFAULT': ['false'], 'INSURANCEOPTIONSELECTED': ['false'], 'CORRELATIONID': ['5f22a1dddd174'], 'PAYMENTINFO_0_TAXAMT': ['0.00'], 'PAYMENTINFO_0_TRANSACTIONID': ['36H74806W7716762Y'], 'PAYMENTINFO_0_ACK': ['Success'], 'PAYMENTINFO_0_PENDINGREASON': ['authorization'], 'PAYMENTINFO_0_AMT': ['86.76'], 'PAYMENTINFO_0_PROTECTIONELIGIBILITY': ['PartiallyEligible'], 'PAYMENTINFO_0_ERRORCODE': ['0'], 'TOKEN': ['EC-6B957889FK3149915'], 'VERSION': ['95.0'], 'SUCCESSPAGEREDIRECTREQUESTED': ['true'], 'BUILD': ['6680107'], 'PAYMENTINFO_0_CURRENCYCODE': ['GBP'], 'TIMESTAMP': ['2013-07-02T13:02:50Z'], 'PAYMENTINFO_0_SECUREMERCHANTACCOUNTID': ['XFQALBN3EBE8S'], 'PAYMENTINFO_0_PROTECTIONELIGIBILITYTYPE': ['ItemNotReceivedEligible'], 'PAYMENTINFO_0_ORDERTIME': ['2013-07-02T13:02:49Z'], 'PAYMENTINFO_0_PAYMENTSTATUS': ['Pending']
^
SyntaxError: invalid syntax
好像我用
msg, paypal_msg = paypal_meta[0].split(' - ')
paypal = ast.literal_eval(paypal_msg)
paypal_dict = {}
for k, v in paypal.items():
paypal_dict[k] = str(v[0])
if paypal_dict:
namespace['payment_gateway'] = { 'paypal' : paypal_dict}
insert = orders_dbs.save(namespace)
return insert
这是可行的,但我不能使用它,因为返回的一些记录没有分割并且不准确。你知道吗
基本上,我想把花括号里的条目从值中去掉方括号,然后从中创建一个新字典。你知道吗
你需要包括花括号,你的代码省略了这些:
请注意,括号现在位于
{...}
的周围。你知道吗或者,如果字典前面总是有一条消息和一个破折号,则可以使用
str.partition()
将其拆分:或者使用
str.split()
将拆分限制为一次:尽量避免将类似的Python结构放入数据库;将JSON存储在单独的列中,而不是对象的字符串转储中。你知道吗
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