<p>以下是我在评论中所描述的内容,加上修改以正确处理Michael Anderson在评论中指出的大矩形内的圆:</p>
<pre><code>import math
def collision(rleft, rtop, width, height, # rectangle definition
center_x, center_y, radius): # circle definition
""" Detect collision between a rectangle and circle. """
# complete boundbox of the rectangle
rright, rbottom = rleft + width/2, rtop + height/2
# bounding box of the circle
cleft, ctop = center_x-radius, center_y-radius
cright, cbottom = center_x+radius, center_y+radius
# trivial reject if bounding boxes do not intersect
if rright < cleft or rleft > cright or rbottom < ctop or rtop > cbottom:
return False # no collision possible
# check whether any point of rectangle is inside circle's radius
for x in (rleft, rleft+width):
for y in (rtop, rtop+height):
# compare distance between circle's center point and each point of
# the rectangle with the circle's radius
if math.hypot(x-center_x, y-center_y) <= radius:
return True # collision detected
# check if center of circle is inside rectangle
if rleft <= center_x <= rright and rtop <= center_y <= rbottom:
return True # overlaid
return False # no collision detected
</code></pre>