Euler 11 Pyth0n项目

2024-04-25 22:12:52 发布

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我正试图解决这个难题,但我无法找出适用于这个例子的逻辑,却打破了解决方案!你知道吗

我认为这与元组的方向列表中的负数有关。你知道吗

任何建议都将不胜感激。!你知道吗

以下是我遇到问题的代码:)

我怎样才能找到四个相邻数字在同一方向上的最大乘积。如下所述?你知道吗

# Largest product in a grid
# Problem 11 
# In the 20×20 grid below, four numbers along a diagonal line have been marked in red.

# The product of these numbers is 26 × 63 × 78 × 14 = 1788696.

# What is the greatest product of four adjacent numbers in the same direction (up, down, left, right, or diagonally) in the 20×20 grid?

grid = [
    [8, 2, 22, 97, 38, 15, 0, 40, 0, 75, 4, 5, 7, 78, 52, 12, 50, 77, 91, 8],
    [49, 49, 99, 40, 17, 81, 18, 57, 60, 87, 17, 40, 98, 43, 69, 48, 4, 56, 62, 0],
    [81, 49, 31, 73, 55, 79, 14, 29, 93, 71, 40, 67, 53, 88, 30, 3, 49, 13, 36, 65],
    [52, 70, 95, 23, 4, 60, 11, 42, 69, 24, 68, 56, 1, 32, 56, 71, 37, 2, 36, 91],
    [22, 31, 16, 71, 51, 67, 63, 89, 41, 92, 36, 54, 22, 40, 40, 28, 66, 33, 13, 80],
    [24, 47, 32, 60, 99, 3, 45, 2, 44, 75, 33, 53, 78, 36, 84, 20, 35, 17, 12, 50],
    [32, 98, 81, 28, 64, 23, 67, 10, 26, 38, 40, 67, 59, 54, 70, 66, 18, 38, 64, 70],
    [67, 26, 20, 68, 2, 62, 12, 20, 95, 63, 94, 39, 63, 8, 40, 91, 66, 49, 94, 21],
    [24, 55, 58, 5, 66, 73, 99, 26, 97, 17, 78, 78, 96, 83, 14, 88, 34, 89, 63, 72],
    [21, 36, 23, 9, 75, 0, 76, 44, 20, 45, 35, 14, 0, 61, 33, 97, 34, 31, 33, 95],
    [78, 17, 53, 28, 22, 75, 31, 67, 15, 94, 3, 80, 4, 62, 16, 14, 9, 53, 56, 92],
    [16, 39, 5, 42, 96, 35, 31, 47, 55, 58, 88, 24, 0, 17, 54, 24, 36, 29, 85, 57],
    [86, 56, 0, 48, 35, 71, 89, 7, 5, 44, 44, 37, 44, 60, 21, 58, 51, 54, 17, 58],
    [19, 80, 81, 68, 5, 94, 47, 69, 28, 73, 92, 13, 86, 52, 17, 77, 4, 89, 55, 40],
    [4, 52, 8, 83, 97, 35, 99, 16, 7, 97, 57, 32, 16, 26, 26, 79, 33, 27, 98, 66],
    [88, 36, 68, 87, 57, 62, 20, 72, 3, 46, 33, 67, 46, 55, 12, 32, 63, 93, 53, 69],
    [4, 42, 16, 73, 38, 25, 39, 11, 24, 94, 72, 18, 8, 46, 29, 32, 40, 62, 76, 36],
    [20, 69, 36, 41, 72, 30, 23, 88, 34, 62, 99, 69, 82, 67, 59, 85, 74, 4, 36, 16],
    [20, 73, 35, 29, 78, 31, 90, 1, 74, 31, 49, 71, 48, 86, 81, 16, 23, 57, 5, 54],
    [1, 70, 54, 71, 83, 51, 54, 69, 16, 92, 33, 48, 61, 43, 52, 1, 89, 19, 67, 48]
]

straight = [(1,0), (0,1), (-1,0), (0,-1)]
diagonal = [(1,1), (-1,1), (1,-1), (-1,-1)]

def prod(lst):
    """ returns the product of a list """
    p = 1
    for i in lst:
        if i != 0: # ignore zeros..
            p *= i
    return p


def traverse(start, steps, grid, direction):
    """ Input a starting point and number of steps to Traverse """  
    x, y = start[0]-1,  start[1]-1  
    print(x, y)
    j, k = direction[0], direction[1]
    print(j, k)
    try:
        for i in range(steps):
            print(grid[x+i+j][y+i+k])
            yield grid[x+i+j][y+i+k]
    except IndexError:
        pass

print()
# Example
d = traverse((6, 8), 4, grid, (1, 1))
p = prod([x for x in d])
print('26 x 63 x 78 x 14 = ', 1788696, p == 1788696, '\nActual:', p) # [26, 63, 78, 14] 1788696
print()
#Answer
d = traverse((15, 3), 4, grid, (1, -1))
p = prod([x for x in d])
print('87 x 97 x 94 x 89 = ', 70600674, p == 70600674, '\nActual:', p) # [87, 97, 94, 89] 70600674

Tags: oftheinforprodproductsteps方向
1条回答
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1楼 · 发布于 2024-04-25 22:12:52

你很接近。下面是经过编辑的代码:

def traverse(start, steps, grid, direction):
    """ Input a starting point and number of steps to Traverse """  
    x, y = start[0],  start[1]  # EDIT: remove "- 1"
    print(x, y)
    j, k = direction[0], direction[1]
    print(j, k)
    try:
        for i in range(steps):
            print(grid[x+i*j][y+i*k])  # EDIT: i*j instead of i+j
            yield grid[x+i*j][y+i*k]   # EDIT: i*j instead of i+j
    except IndexError:
        pass

print()
# Example
d = traverse((6, 8), 4, grid, (1, 1))
p = prod([x for x in d])
print('26 x 63 x 78 x 14 = ', 1788696, p == 1788696, '\nActual:', p) # [26, 63, 78, 14] 1788696
print()
#Answer
d = traverse((15, 3), 4, grid, (-1, 1))  # EDIT: fix direction
p = prod([x for x in d])
print('87 x 97 x 94 x 89 = ', 70600674, p == 70600674, '\nActual:', p) # [87, 97, 94, 89] 70600674

我对您的代码所做的所有编辑都进行了注释,以使其正常工作。如果您有任何问题,请在下面发表评论。你知道吗

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