我想检查每个Threads
(即order_threads_message
)中所有MessageState
的Message
,如果任何线程都隐藏了所有消息,那么也将该线程设为隐藏线程(/或者从消息顺序中删除它)。我想在视图中这样做,然后再将其传递给模板。我该怎么做?如果你不明白我的意思,请问我。我很乐意解释。请帮助我如何在视图中执行此操作。我会很感激的。非常感谢。你知道吗
你知道吗型号.py地址:
class Thread(models.Model):
subject = models.CharField(max_length=50, blank=True, null=True)
user = models.ManyToManyField(User)
class ThreadState(models.Model):
thread = models.ForeignKey(Thread)
user = models.ForeignKey(User)
thread_hidden = models.BooleanField(default=False)
class Message(models.Model):
thread = models.ForeignKey(Thread)
sender = models.ForeignKey(User)
sent_date = models.DateTimeField(default=datetime.now)
body = models.TextField()
class MessageState(models.Model):
message = models.ForeignKey(Message)
user = models.ForeignKey(User)
read = models.BooleanField(default=False)
message_hidden = models.BooleanField(default=False)
你知道吗视图.py你知道吗
@login_required
def message(request):
user = request.user
threads = user.thread_set.all()
order_threads_message = threads.annotate(max_sent_date=Max('message__sent_date')).order_by('-max_sent_date')
if order_threads_message.count() > 0:
recent_thread = order_threads_message[0]
if recent_thread.message_set.all().count() > 0:
recent_thread_conversations = recent_thread.message_set.all()
return render(request, 'conversations.html', {
'all_threads':order_threads_message,
'conversations':recent_thread_conversations,
'active': recent_thread.id
})
else:
recent_thread_conversations = 0
return render(request, 'conversations.html', {
'all_threads':order_threads_message,
'conversations':recent_thread_conversations,
'active': recent_thread.id
})
else:
order_threads_message = 0
recent_thread_conversations = 0
return render(request, 'conversations.html', {
'all_threads':order_threads_message,
'conversations':recent_thread_conversations,
})
我已对以下模型运行了此查询:
型号
查询
如果查询的
MessageState
的message_hidden
中至少有一个是False
,则此查询将返回Thread
对象。你知道吗相关问题 更多 >
编程相关推荐