我正试图用Python向收件人列表发送电子邮件,但有人告诉我先连接。你知道吗
import smtplib
try:
s = smtplib.SMTP('smtp.xxx.com', 587)
s.starttls()
s.login('barbaramilleraz@xxx.com', 'xxx')
message = '''
...message text...
'''
s.connect()
with open('players.txt') as f:
email = f.readlines()
email = [e.strip() for e in email]
for person in range(len(email)):
print('Sending email to {}'.format(email[person]))
s.sendmail('barbaramilleraz', email[person], message)
except(smtplib.SMTPSenderRefused):
pass
输出为:
C:\Users\BMiller>python mailing.py
Sending email xxx@xxx.com
Sending email to xxx@xxx.com
Traceback (most recent call last):
File "mailing.py", line 25, in <module>
s.sendmail('barbaramilleraz', email[person], message)
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 852, in sendmail
self.ehlo_or_helo_if_needed()
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 600, in ehlo_or_helo_if_needed
if not (200 <= self.ehlo()[0] <= 299):
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 440, in ehlo
self.putcmd(self.ehlo_msg, name or self.local_hostname)
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 367, in putcmd
self.send(str)
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 359, in send
raise SMTPServerDisconnected('please run connect() first')
smtplib.SMTPServerDisconnected: please run connect() first
我是Python新手,所以我不知道如何继续。你知道吗
谢谢你。你知道吗
正如dcg在评论中所说的,在发送电子邮件之前,您必须调用
s.connect()
来建立连接。你知道吗当你这么做的时候,你提到它只发送一次:这是因为你在发送每一条消息之后都在给
s.quit()
打电话。一旦你做了那件事,s
就没有任何意图和目的了:如果你想再次使用它,你必须重新启动配置。你知道吗所以,在发送所有消息之前,先给
s.connect()
打一次电话,在你完全处理完s
之前,不要给s.quit()
打电话。你知道吗如果想法是在引发异常时跳过收件人,那么异常处理应该围绕地址循环中的sendmail调用。你知道吗
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