<p>为什么不试试呢?</p>
<p>您感兴趣的两个平台的驱动程序是可用的——python(<em>redis</em>,通过包索引]<a href="http://pypi.python.org/pypi" rel="noreferrer">2</a>)和R(<em>rredis</em>,<a href="http://cran.r-project.org/" rel="noreferrer">CRAN</a>)。</p>
<p>redis的天才之处在于它能够神奇地识别NumPy数据类型,并允许您插入和提取多维NumPy数组,就好像它们是原生的redis数据类型一样,而它的天才之处在于您只需几行代码就可以轻松地创建这样的接口。</p>
<p>python中有(至少)几个关于redis的教程;<a href="http://degizmo.com/2010/03/22/getting-started-redis-and-python/" rel="noreferrer">DeGizmo blog</a>上的教程特别好。</p>
<pre><code>import numpy as NP
# create some data
A = NP.random.randint(0, 10, 40).reshape(8, 5)
# a couple of utility functions to (i) manipulate NumPy arrays prior to insertion
# into redis db for more compact storage &
# (ii) to restore the original NumPy data types upon retrieval from redis db
fnx2 = lambda v : map(int, list(v))
fnx = lambda v : ''.join(map(str, v))
# start the redis server (e.g. from a bash prompt)
$> cd /usr/local/bin # default install directory for 'nix
$> redis-server # starts the redis server
# start the redis client:
from redis import Redis
r0 = Redis(db=0, port=6379, host='localhost') # same as: r0 = Redis()
# to insert items using redis 'string' datatype, call 'set' on the database, r0, and
# just pass in a key, and the item to insert
r0.set('k1', A[0,:])
# row-wise insertion the 2D array into redis, iterate over the array:
for c in range(A.shape[0]):
r0.set( "k{0}".format(c), fnx(A[c,:]) )
# or to insert all rows at once
# use 'mset' ('multi set') and pass in a key-value mapping:
x = dict([sublist for sublist in enumerate(A.tolist())])
r0.mset(x1)
# to retrieve a row, pass its key to 'get'
>>> r0.get('k0')
'63295'
# retrieve the entire array from redis:
kx = r0.keys('*') # returns all keys in redis database, r0
for key in kx :
r0.get(key)
# to retrieve it in original form:
A = []
for key in kx:
A.append(fnx2(r0.get("{0}".format(key))))
>>> A = NP.array(A)
>>> A
array([[ 6., 2., 3., 3., 9.],
[ 4., 9., 6., 2., 3.],
[ 3., 7., 9., 5., 0.],
[ 5., 2., 6., 3., 4.],
[ 7., 1., 5., 0., 2.],
[ 8., 6., 1., 5., 8.],
[ 1., 7., 6., 4., 9.],
[ 6., 4., 1., 3., 6.]])
</code></pre>