有没有办法从一张单子里找出最好的一个人，然后把它加到单子上？

Question

我正在建立一个名单，其中我有几个人与编程技能和他们的现行利率。我现在处于困境，因为我正试图从名单中找到最好的个人大约，根据他们的技能涵盖每一美元。我应该用什么算法来评估孤立的个体？你知道吗

我一直试图让for循环迭代，但它没有移动位置。只看第一个细胞就结束了。你知道吗

jess = (["php", "java"], 200)

clark = (["php", "c++", "go"], 1000)

john = (["lua"], 500)

cindy = (["php", "go", "word"], 240)

candidates = [jess, clark, john, cindy]

project = ["php", "java", "c++", "lua", "go"]

def team_of_best_individuals(project, candidates):       

##note that in the list candidates, I tried to divide the number of items in the tuple by the cost, in order to find the skill per dollar

   def team_of_best_individuals(project, candidates):
   skillList = []
   for name in (candidates):
       len(name)
       for skill in name[0]:
            skillList.append(skill)

            if len(skillList) == len(name):
                num_of_skills=len(skillList)
                cost = name[1]
                num_skill_per_dollar = num_of_skills/cost
                return num_skill_per_dollar, candidates[0:4]
print("skill per dollar="+str(team_of_best_individuals(project, candidates)))

预期（产出）必须是每一美元拥有最多技能的人。返回值必须是列表中人员的位置整数。你知道吗

例如

0 - 4

Answer 1

漂亮优雅的回答@Mark Meyer， 我想在这里补充一点，我认为你的问题中遗漏了这一点。它需要寻找作为项目一部分的技能。如果应聘者拥有的任何技能不属于这一部分，就必须打折扣。 我试着写些有用的东西那个。作为他指出，单独使用候选名称而不是变量名称可能是值得的。你知道吗

jess = (["php", "java"], 200)

clark = (["php", "c++", "go"], 1000)

john = (["lua"], 500)

cindy = (["php", "go", "word"], 240)

candidates = [jess, clark, john, cindy]

project = ["php", "java", "c++", "lua", "go"]

def team_of_best_individuals(project, candidates):
    best = ('A', 0)
    for ind, candidate in enumerate(candidates):
        skills = candidate[0]
        skillperdollar = len([skill for skill in skills if skill in project])/candidate[1]
        if skillperdollar > best[1]:
            best = (ind, skillperdollar)
    return best