def foo(self, x):
if x > 5:
y = 2 #for workaround with pass by reference method
return true , y
# calling it by
i = 0
for i in range (0,10):
if foo(i):
ref_value = y #to get the reference value
>>> def foo(i):
... if i > 5:
... y = 2
... return True, y
... return False,0
...
>>> for i in range(0,10):
... x,y = foo(i)
... if x:
... ret_value = y
... else:
... ret_value = 0
... print(ret_value)
...
0
0
0
0
0
0
2
2
2
2
>>> type(foo(6)) #Example to show type of value returned.
<class 'tuple'>
是的,上面的代码返回一个
tuple
,您可以返回这样的多个值(在一个元组或一个列表中,等等),但是您也必须在调用端接受它们(unpack)(要么全部接受,要么将元组/列表作为单个元素接受)。示例/演示-是的,您需要从返回的结果中解压这两个值:
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