我想补充一下温度转换器但当我测试它时,代码无法识别我输入的数字来选择操作。 还有一种方法可以使用列表同时添加多个数字吗
#Returns the sum of num1 and num2
def add(num1, num2):
return num1 + num2
#Returns the result of subtracting num1 - num2
def sub(num1, num2):
return num1 - num2
#Returns the result of multiplying num1 * num2
def mul(num1, num2):
return num1 * num2
#Returns the result of dividing num1 / num2
def div(num1, num2):
return num1 / num2
#Returns the result of dividing num1 / num2
def exp(num1, num2):
return num1 ** num2
from math import *
print("1: ADDITION")
print("2: SUBTRACTION")
print("3: MULTIPLICATION")
print("4: DIVISION")
print("5: Exponent")
print("6: Square root")
print("7: ")
print("8:")
print("9:")
print("10:")
def main():
operation = int(input("operation:"))
if(operation == '1'):
a = var1("input a:")
b = var2("input b:")
print(add(var1, var2))
elif(operation == '2'):
a = var1("input a:")
b = var2("input b:")
print(sub(var1, var2))
elif(operation == '3'):
a = var1("input a:")
b = var2("input b:")
print(div(var1, var2))
elif(operation == '4'):
a = var1("input a:")
b = var2("input b:")
print(mul(var1, var2))
elif(operation == '5'):
a = var1("input a:")
b = var2("input b:")
print(exp(var1, var2))
elif(operation == '6'):
a = var1("input:")
print(sqrt(var1,))
elif(operation == '7'):
a = var1("input a:")
b = var2("input b:")
print(add(var1, var2))
else:
main()
main()
您可以利用Python中的
operator
模块并使用字典分派方法,例如:相关问题 更多 >
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