Python列表名称语法

Question

在第二个函数中，我在listExpenseNames列表中不断得到一个语法错误。我尝试将变量的名称更改为ExpenseNamesList，但出现了相同的错误。对于这两个变量名，我也用0作为索引进行了测试，但这也没有什么区别。任何帮助都将不胜感激。另外，请不要试图纠正我的代码中可能存在的任何其他错误，我想通过犯错误来学习自己。（这可能看起来很矛盾，因为我刚刚发布了一个请求修复的帖子，但那只是因为我被难住了，它阻止了我继续前进。）

def inputExpenseNames():
    listExpenseNames =[]
    loopExpenseNames = y
    while loopExpenseNames == y:
        listExpenseNames.append = input('Please enter the expense name.')
        loopExpenseNames=input('Would you like to enter another expense? If so, please enter \'y\'')
    print(listExpenseNames)

def inputExpenseAmounts():
    listExpenseAmounts =[]
    loopExpenseAmounts = 0
    while loopExpenseAmounts <= len(inputExpenseNames) :
        listExpenseAmounts.append = input('How much was spent on' listExpenseNames[int(loopExpenseAmounts)]'?')
        loopExpenseAmounts += 1
    print(listExpenseAmounts)

Answer 1

我假设您想要打印listExpenseNames[int（loopExpenseAmounts）]中存储的字符串作为输入显示文本。您需要将带+的字符串连接到一个字符串中，而不仅仅是在每个字符串后面列出它们：

listExpenseAmounts.append = input('How much was spent on' + listExpenseNames[int(loopExpenseAmounts)] + '?')

Answer 2

此代码有几个问题：

1. listExpenseNames不会在inputExpenseAmounts内定义。See Here解释一下
2. l.append = ...将更改append属性的值，它实际上不会附加任何内容。附加某事做l.append(...)
3. 正如其他人指出的，使用+连接字符串：'spent on' + listExpenseNames[int(loopExpenseAmounts)] + '?'

`

Answer 3

您正试图在下一行连接字符串，但没有。请尝试以下代码。你知道吗

listExpenseAmounts.append(input('How much was spent on'+ listExpenseNames[int(loopExpenseAmounts)]'?'))