pythontkinter切断了路径，但作为完整目录打开

Question

下面是我的完整Python代码：

from tkinter import *
import glob
import os
from PIL import Image, ImageTk, ImageGrab
import tkinter as tk
import pyautogui
import datetime

#date & time
now = datetime.datetime.now()

root = tk.Tk()
root.title("SIGN OFF")
root.minsize(840, 800)

# Add a grid
mainframe = tk.Frame(root)
mainframe.columnconfigure(0, weight=1)
mainframe.rowconfigure(0, weight=1)
mainframe.pack(pady=100, padx=100)

# Create a Tkinter variable
tkvar = tk.StringVar(root)


# Directory
directory = "C:/Users/eduards/Desktop/work/data/to-do"
choices = glob.glob(os.path.join(directory, "*.jpg"))
tkvar.set('...To Sign Off...') # set the default option

# Dropdown menu
popupMenu = tk.OptionMenu(mainframe, tkvar, *choices)
tk.Label(mainframe, text="Choose your sign off here:").grid(row=1, column=1)
popupMenu.grid(row=2, column=1)

label2 = tk.Label(mainframe, image=None)
label2.grid(row = 4, column = 1, rowspan = 10)

# On change dropdown callback.
def change_dropdown(*args):
    """ Updates label2 image. """
    imgpath = tkvar.get()
    img = Image.open(imgpath)
    img = img.resize((240,250))
    photo = ImageTk.PhotoImage(img)
    label2.image = photo
    label2.configure(image=photo)


tk.Button(mainframe, text="Open", command=change_dropdown).grid(row=3, column=1)


def var_states():
    text_file = open("logfile.txt", "a")
    text_file.write("TIME: %s, USER: %s, One %d, Two %d\n" % (now,os.getlogin(), var1.get(), var2.get()))
    text_file.close()
    print("One %d, Two %d" % (var1.get(), var2.get()))

var1 = IntVar()
Checkbutton(mainframe, text="Ingredients present in full (any allergens in bold with allergen warning if necessary)", variable=var1).grid(column = 2, row=1, sticky=W)
var2 = IntVar()
Checkbutton(mainframe, text="May Contain Statement.", variable=var2).grid(column = 2, row=2, sticky=W)
var3 = IntVar()
Checkbutton(mainframe, text="Cocoa Content (%).", variable=var3).grid(column = 2, row=3, sticky=W)
var4 = IntVar()
Checkbutton(mainframe, text="Vegetable fat in addition to Cocoa butter", variable=var4).grid(column = 2, row=4, sticky=W)
var5 = IntVar()
Checkbutton(mainframe, text="Instructions for Use.", variable=var5).grid(column = 2, row=5, sticky=W)
var6 = IntVar()
Checkbutton(mainframe, text="Additional warning statements (pitt/stone, hyperactivity etc)", variable=var6).grid(column = 2, row=6, sticky=W)
var7 = IntVar()
Checkbutton(mainframe, text="Nutritional Information Visible", variable=var7).grid(column = 2, row=7, sticky=W)
var8 = IntVar()
Checkbutton(mainframe, text="Storage Conditions", variable=var8).grid(column = 2, row=8, sticky=W)
var9 = IntVar()
Checkbutton(mainframe, text="Best Before & Batch Information", variable=var9).grid(column = 2, row=9, sticky=W)
var10 = IntVar()
Checkbutton(mainframe, text="Net Weight & Correct Font Size.", variable=var10).grid(column = 2, row=10, sticky=W)
var11 = IntVar()
Checkbutton(mainframe, text="Barcode - Inner", variable=var11).grid(column = 2, row=11, sticky=W)
var12 = IntVar()
Checkbutton(mainframe, text="Address & contact details correct", variable=var12).grid(column = 2, row=12, sticky=W)

def user():
    user_input = os.getlogin()
    tk.Label(mainframe, text = user_input, font='Helvetica 18 bold').grid(row = 0, column = 1)


user()


def save():
    # pyautogui.press('alt')
    # pyautogui.press('printscreen')
    # img = ImageGrab.grabclipboard()
    # img.save('paste.jpg', 'JPEG')

    var_states()


tk.Button(mainframe, text = "Save", command = save).grid(row = 20, column = 1)


root.mainloop()

当我运行代码时，会有一个jpg文件的下拉列表。当前它显示完整目录，如下所示：

我在前面写了一篇关于如何修剪路径的帖子，内容如下：

files = os.listdir("C:/Users/eduards/Desktop/work/data/to-do")
print(files)

但是如果我使用上面的代码，它在单击open时不会打开路径，因为它没有完整的路径名。你知道吗

我要做的是，为了显示的目的，减少路径名，然后按照原来的完整路径打开图像。你知道吗

例如：

当前下拉菜单显示C:/Users/eduards/Desktop/work/data/to-do/img1.jpg 我想要的结果是img1.jpg，但是在后台打开上面的整个路径。你知道吗

Copy comment: this is what I have tried

directory = os.path.splitdrive("C:/Users/eduards/Desktop/work/data/to-do")
choices = glob.glob(os.path.join(directory[1:], "*.jpg"))

, but says

expected str, bytes or os.Pathlike, not tuple. 

Have added [1:] because the path is split into 2 and returning the 2nd part of it.

Answer 1

Question: Show only the filename in OptionMenu but get original full path from selection.

创建您自己的OptionMenu，它保存所有图像的dict完整路径，并且仅将文件名显示为选项。你知道吗

---

1. 通过从(tk.OptionMenu)继承来定义自己的小部件FileNameOptionMenu

   class FileNameOptionMenu(tk.OptionMenu):
       def __init__(self, parent, directory, extension, callback):
   

2. 从所有图像获取完整路径并提取filename。
   使用filename作为key和value作为dict保存每个完整路径。

           # Save result from `glob` in a `dict`
           self.glob = {}
           for fpath in glob.glob(os.path.join(directory, "*.{}".format(extension))):
               filename, extension = os.path.splitext(os.path.split(fpath)[1])
               self.glob[filename] = fpath
   

3. 定义一个保存所选选项的变量，以备以后使用。
   从dict继承的tk.OptionMenu用list的keys初始化。
   将class method self.command作为command=传递。
   保存callback以备以后使用。你知道吗

           self.selected = tk.StringVar(parent, 'Select a image...')
           super().__init__(parent, self.selected, *list(self.glob),
                            command=self.command)
   
           self.callback = callback
   
   

4. 这个class method在每次单击选项选择时都会被调用。 在调用时，它使用所选选项的完整路径调用self.callback，即ImageLabel.configure。

       def command(self, val):
           self.callback(image=self.glob.get(self.selected.get()))
   

5. 通过从(tk.Label)继承来定义自己的小部件ImageLabel。
   这个类扩展了tk.Label.configure来处理.configure(image=<full path>，而不是.configure(image=<image object>。

   class ImageLabel(tk.Label):
       def __init__(self, parent):
           super().__init__(parent, image=None)
   

6. 重载继承的class method tk.Label.configure。
   捕获name参数image=，并用image object替换传递的完整路径。你知道吗

       def configure(self, **kwargs):
           key = 'image'
           if key in kwargs:
               # Replace the filepath with the image
               fpath = kwargs[key]
   
               img = Image.open(fpath)
               img = img.resize((240, 250))
               self._image = ImageTk.PhotoImage(img)
   
               kwargs[key] = self._image
   

7. 调用原始的tk.Label.configure来显示图像

           super().configure(**kwargs)
   

Usage:

import tkinter as tk
from PIL import Image, ImageTk
import glob, os

class App(tk.Tk):
    def __init__(self):
        super().__init__()

        self.label_image = ImageLabel(parent=self)
        self.label_image.grid(row=2, column=0)

        self.option_menu = \
            FileNameOptionMenu(parent=self,
                               directory='C:/Users/eduards/Desktop/work/data/to-do',
                               extension='jpg',
                               callback=self.label_image.configure
                                               )
        self.option_menu.grid(row=0, column=0)


if __name__ == "__main__":
    App().mainloop()

用Python:3.5测试