我想写一个程序,让我尽可能少的议案,使一个LBP的变化。你知道吗
import sys
n = int(sys.argv[1])
if n%100==0:
print(n//100, " LBP ", 10**5)
elif n//100!=0 and n%50==0:
print(n//100, " LBP ", 10**5)
m = n-100*(n//100)
print(m//50, " LBP ", 5*(10**4))
elif n//100!=0 or n//50!=0 and n%20==0:
print(n//100, " LBP ", 10**5)
m = n-100*(n//100)
print(m//50, " LBP ", 5*(10**4))
o = m - 50*(m//50)
print(o//20, " LBP ", 2*(10**4))
elif n//100!=0 or n//50!=0 or n//20!=0 and n%10==0:
print(n//100, " LBP ", 10**5)
m = n-100*(n//100)
print(m//50, " LBP ", 5*(10**4))
o = m - 50*(m//50)
print(o//20, " LBP ", 2*(10**4))
p = o - 20*(o//20)
print(p//10, " LBP ", (10**4))
elif n//100!=0 or n//50!=0 or n//20!=0 or n//10!=0 and n%5==0:
print(n//100, " LBP ", 10**5)
m = n-100*(n//100)
print(m//50, " LBP ", 5*(10**4))
o = m - 50*(m//50)
print(o//20, " LBP ", 2*(10**4))
p = o - 20*(o//20)
print(p//10, " LBP ", (10**4))
q = p - 10*(p//10)
print(n//5, " LBP ", 5*(10**3))
elif n//100!=0 or n//50!=0 or n//20!=0 or n//10!=0 or n//5!=0 and n%1==0:
print(n//100, " LBP ", 10**5)
m = n-100*(n//100)
print(m//50, " LBP ", 5*(10**4))
o = m - 50*(m//50)
print(o//20, " LBP ", 2*(10**4))
p = o - 20*(o//20)
print(p//10, " LBP ", (10**4))
q = p - 10*(p//10)
print(n//5, " LBP ", 5*(10**3))
r = q - 5*(q//10)
print(n-m-o-p-q-r, " LBP ", 10**3)
它对某些数字不起作用,例如134。 你能帮我修一下吗?或者你能建议其他的写作方法吗?你知道吗
谢谢你的帮助。你知道吗
这应该起作用:
使用循环和函数,它可以被清理很多。你知道吗
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