嗨,我正在做一个Python猜测游戏程序,我不能减少一个值。这是我的程序:
import random as rand
print('\t\t\tGuess Game\n')
print('Enter a Number Between 1 and 20')
while True:
a = rand.randint(1, 20)
for i in range(1, 5):
guess = 0
guess = int(input('Enter a Number : '))
if guess == a:
print('You Are Right\n')
break
if guess == 0 or guess < 0:
print('Please Enter a Positive Integer\n')
i -= 1
continue
if guess > 20:
print('Please Enter a Reasonable Number\n')
i -= 1
continue
if guess > a:
if guess <= (a + 5):
print('Your Number is Little High\n')
else:
print('Your Number is Too High\n')
if guess < a:
if guess >= (a - 5):
print('Your Number is Little Low\n')
else:
print('Your Number is Too Low\n')
if guess != a:
print('My Number Was %s. Please try The Program Again If You Like\n' % a)
play = str(input('Do You Want to play Again? '))
play.lower()
if play.startswith('y'):
continue
elif play.startswith('n'):
break
else:
while play is not ((play.startswith('y') and play.endswith('s')) or play == 'y') or ((play.startswith('n') and play.endswith('o')) or play == 'n'):
play = input('Please Enter a Yes or No')
i-=1不起作用。你知道吗
谢谢。你知道吗
编辑 当使用负整数时,需要进行7次猜测
随机导入为rand
i=5#猜测次数 a=兰特。兰丁(1,20)
当i>;0时: guess=int(input())
if guess == a:
print("You won!")
break
if guess == 0:
i = i + 1
continue
i = i - 1
使用for循环,在每次迭代中设置
i
。因此,如果从i
变量中减去一,它将被简单地设置回应该的值(从5减到1)。要使循环一直运行到玩家猜不出为止,请执行以下操作:如果玩家猜对了,“你赢了!”将被打印,循环将结束。如果玩家猜不到,循环也会结束,但不会打印消息。你知道吗
如果你想检查玩家是否赢了,只要做
i > 0
。这将是真实的,如果球员赢了,因为仍将有一些猜测剩余。你知道吗相关问题 更多 >
编程相关推荐