我只是试图修改一个字符串并返回修改后的字符串,但是在打印变量时返回“None”。你知道吗
def AddToListTwo(self,IndexPosition):
filename = RemoveLeadingNums(self, str(self.listbox1.get(IndexPosition))) #get the filename, remove the leading numbers if there are any
print filename #this prints None
List2Contents = self.listbox2.get(0, END)
if(filename not in List2Contents): #make sure the file isn't already in list 2
self.listbox2.insert(0, filename)
def RemoveLeadingNums(self, words):
if(isinstance(words,str)):
match = re.search(r'^[0-9]*[.]',words)
if match: #if there is a match, remove it, send it through to make sure there aren't repeating numbers
RemoveLeadingNums(self, re.sub(r'^[0-9]*[.]',"",str(words)).lstrip())
else:
print words #this prints the value correctly
return words
if(isinstance(words,list)):
print "list"
编辑-多人评论说,如果存在匹配项,我不会返回值。如果有的话,我不想退货。它可能是重复的(例如:1.2。项目a)。所以,我想基本上使用递归来删除它,然后返回值
如果是火柴你什么也不退。应该是:
有多个条件
RemoveLeadingNums
返回None
。e、 g.如果采用if match:
分支。也许应该是:如果有任何数据类型不是传入的字符串,则还返回
None
。你知道吗相关问题 更多 >
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