如何从预先拆分的字符串中获取列表？

Question

所以有一个字符串foo = 'asdfasdfzxc<test>afx<one>'
如何获得bar = ['asdfasdfzxc','test','afx','one']？你知道吗

Answer 1

试试看

import re
foo = 'asdfasdfzxc<test>afx<one>'
bar = re.split(r'[\<\>]',foo)[:-1]
bar.remove('afx')

bar
Out[89]:
['asdfasdfzxc', 'test', 'one']