如何在Python中合并两个不同长度的列表

Question

在python3中，我看到了两个不同长度的合并列表。我在这里已经讨论了很多其他的话题，但似乎没有一个能解决我的问题。你知道吗

我有：

List1 = ['A','B','C']
List2 = ['ab', 'ac', 'ad', 'ae']

Output = [['Aab', 'Aac', 'Aad', 'Aae'],['Bab','Bac','Bad','Bae'],['Cab','Cac','Cad','Cae']]

提前谢谢！你知道吗

更新--感谢ndclt为上述问题提供的解决方案。你知道吗

我真正的问题是：

List1 = ['A','B','C']
List2 = ['a','b','c','d','e','f','g','h','i']

Output desired = ['Aa', 'Ab', 'Ac', 'Bd', 'Be', 'Bf', 'Cg', 'Ch', 'Ci']

Answer 1

这是一条单行线：

它使用for循环理解创建嵌套列表。你知道吗

List1 = ['A','B','C']
List2 = ['ab', 'ac', 'ad', 'ae']

out = [[an + bn for bn in List2] for an in List1]
print(out)
# >>> [['Aab', 'Aac', 'Aad', 'Aae'], ['Bab', 'Bac', 'Bad', 'Bae'], ['Cab', 'Cac', 'Cad', 'Cae']]

Answer 2

试试这个：

list1 = ['A','B','C']
list2 = ['ab', 'ac', 'ad', 'ae']
lst = []
finaly_lst = []
for i in list1:
    for j in list2:
        lst.append(i+j)
    finaly_lst.append(lst)
    lst = []
print(finaly_lst)

输出：

[['Aab', 'Aac', 'Aad', 'Aae'], ['Bab', 'Bac', 'Bad', 'Bae'], ['Cab', 'Cac', 'Cad', 'Cae']]

Answer 3

不是很好，但它很有效：

List1 = ['A','B','C']
List2 = ['ab', 'ac', 'ad', 'ae']

final = []
for one in List1:
    intermediate = []
    for two in List2:
        intermediate.append(one+two)
    final.append(intermediate)

print(final)

[['Aab', 'Aac', 'Aad', 'Aae'], ['Bab', 'Bac', 'Bad', 'Bae'], ['Cab', 'Cac', 'Cad', 'Cae']]

如果嵌套不是强制性的：

from itertools import product
List1 = ['A','B','C']
List2 = ['ab', 'ac', 'ad', 'ae']

final = [one+two for one, two in product(List1, List2)]
print(final)

['Aab', 'Aac', 'Aad', 'Aae', 'Bab', 'Bac', 'Bad', 'Bae', 'Cab', 'Cac', 'Cad', 'Cae']