擅长:python、mysql、java
<pre><code>def alignment(nums,j,target):
for row in nums: # get each row
counter = 0
for i in row: # get each number
if i != target: # check if some other number was gotten
if counter == j:
return True
counter = 0 # reset counter
continue
counter += 1
if counter == j:
return True
return False
</code></pre>
<p>不需要<code>n</code>参数。你知道吗</p>