如何获得键值最低的词典

Question

这是我的字典模式。你知道吗

f = { 'client_id': {'client_name': [{'transaction_date': date_time,
                                     'transaction_amount': value_in_dollar}]
                   }
    }

如何得到一个事务量最低的字典。你知道吗

输入示例：

f = { 905220: {'Steven Jhon': [{'transaction_date': '2016-05-07 00:00:00+00',
                              'transaction_amount': 1198},
                             {'transaction_date': '2016-05-08 00:00:00+00',
                              'transaction_amount': 4889}]
              },
      905221: {'Chris Chris': [{'transaction_date': '2016-05-01 00:00:00+00',
                                  'transaction_amount': 50},
                                 {'transaction_date': '2016-05-02 00:00:00+00',
                                  'transaction_amount': 100},
                                 {'transaction_date': '2016-05-03 00:00:00+00',
                                  'transaction_amount': 10}]
               }     
    }

期望输出：

f = { 905220: {'Steven Jhon': [{'transaction_date': '2016-05-07 00:00:00+00',
                              'transaction_amount': 1198}]
              },
      905221: {'Chris Chris': [{'transaction_date': '2016-05-03 00:00:00+00',
                                  'transaction_amount': 10}]
               }     
    }

Answer 1

你可以使用一个大的dict理解，或者像这样的助手函数：

def get_min_by_value(x):
  if isinstance(x, dict):
    return {k: get_min_by_value(v) for k, v in x.items()}
  elif isinstance(x, list):
    return [min(x, key=lambda d: d['transaction_amount'])]

out = get_min_by_value(f)