我想暂停的确切位置的代码,并等待不同的输入加上开始按钮点击。但是,如果无法实现,如何在“开始”按钮中添加另一个按钮以使其工作?你知道吗
import wx
import time
import RPi.GPIO as GPIO
global Total_Length
Total_Length = 500
global Input_Length
Input_Length = 0
a = 0
class tyler(wx.Frame):
def __init__(self,parent,id):
wx.Frame.__init__(self,parent,id,'Lyquid Crystal Laser Control',size=(500,200))
panel=wx.Panel(self)
#global Text_1
self.Text_1 = wx.TextCtrl(panel,-1,"0",(350,30),(50,30))
self.Text_1.Bind(wx.EVT_TEXT_ENTER,self.Start)
self.Text_1.Bind(wx.EVT_KILL_FOCUS,self.Start)
self.timer = wx.Timer(self)
#self.Bind(wx.EVT_TIMER, self.timer)
button_1=wx.Button(panel,label="Start",pos=(400,80),size=(80,30))
button_2=wx.Button(panel,label="Stop",pos=(400,120),size=(80,30))
self.Bind(wx.EVT_BUTTON, self.Start, button_1)
#self.Bind(wx.EVT_BUTTON, self.Stop, button_2)
def Start(self,event):
global a
Input_Length=float(self.Text_1.GetValue())
#print(Input_Length)
#a = Input_Length
#print(Input_Length)
dc=float(100*Input_Length/Total_Length)
GPIO.setmode(GPIO.BCM)
GPIO.setup(18,GPIO.OUT)
GPIO.setwarnings(False)
p = GPIO.PWM(18,1150)
p.start(0)
p.ChangeDutyCycle(dc)
p.ChangeFrequency(1150)
#I wanted to pause the code at here, until the input changes, and the start button clicked, so I add timer in below, however, the output is only a pulse but the square wave is what I wanted
if a == dc:
self.timer.Start(1000)
else:
a = dc
self.timer.Stop()
#def Stop(self,event):
GPIO.cleanup()
if __name__=='__main__':
app=wx.PySimpleApp()
frame=tyler(parent=None,id=-1)
frame.Show()
app.MainLoop()
“暂停并等待”和“事件驱动GUI编程”不能同时使用。只要主GUI线程在等待某个东西时被阻塞,那么其他事件就不能被处理,程序就会被冻结。你的选择是改变你“等待”的方式(实际上不是等待)或者使用另一个线程。你知道吗
This answer另一个问题同样适用于这里,并将为您提供更多信息和指针。你知道吗
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