我正在尝试使用Python从以下XML中获取一个值,但我不确定如何做到这一点:
<feed xmlns="http://www.w3.org/2005/Atom" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:geo="http://www.w3.org/2003/01/geo/wgs84_pos#" xmlns:apple-wallpapers="http://www.apple.com/ilife/wallpapers" xmlns:g-custom="http://base.google.com/cns/1.0" xmlns:taxo="http://purl.org/rss/1.0/modules/taxonomy/" xmlns:opensearch="http://a9.com/-/spec/opensearch/1.1/" xmlns:media="http://search.yahoo.com/mrss/" xmlns:sy="http://purl.org/rss/1.0/modules/syndication/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:georss="http://www.georss.org/georss/" xmlns:creativeCommons="http://backend.userland.com/creativeCommonsRssModule" xmlns:cc="http://web.resource.org/cc/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:g-core="http://base.google.com/ns/1.0">
<title>Feed from some link here</title>
<link rel="self" href="https://somelinkhere/folder/?parameter=abc" />
<link rel="first" href="https://somelinkhere/folder/?parameter=abc" />
<id>https://somelinkhere/folder/?parameter=abc</id>
<updated>2018-03-06T17:48:09Z</updated>
<dc:creator>company.com</dc:creator>
<dc:date>2018-03-06T17:48:09Z</dc:date>
<opensearch:totalResults>4</opensearch:totalResults>
<opensearch:startIndex>1</opensearch:startIndex>
我在找最后一行。我该如何获得out<opensearch:totalResults>4</opensearch:totalResults>
的号码?你知道吗
感谢您的帮助。你知道吗
编辑:
这是我目前正在尝试的代码:
r= requests.get("https://somelinkhere/folder/?parameter=abc", auth=HTTPBasicAuth('username', 'password'))
print r.text
print r.status_code
root = lxml.etree.fromstring(r)
textelem = root.find("opensearch:totalResults")
print textelem.text
然后得到以下错误:
Traceback (most recent call last):
File "tickets.py", line 14, in <module>
root = lxml.etree.fromstring(r)
File "src/lxml/lxml.etree.pyx", line 3213, in lxml.etree.fromstring (src/lxml/lxml.etree.c:82934)
File "src/lxml/parser.pxi", line 1818, in lxml.etree._parseMemoryDocument (src/lxml/lxml.etree.c:124513)
ValueError: can only parse strings
必须在代码中添加r.text。你知道吗
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