擅长:python、mysql、java
<p>最高EGR=0</p>
<p>对于youtube\u usa\u视频中的行:</p>
<pre><code>comments = row [8]
views = row [5]
title = row [1]
if int (views) > 0:
EGR = int (comments) / int (views)
if EGR > highest_EGR:
highest_EGR = EGR
top_vid = title
print (top_vid, highest_EGR)
</code></pre>
<p>好吧,我只是改变了“如果”的观点!=0:'to'如果视图大于0:'and removed'else:'</p>