用缺少的元素格式化字符串

Question

我有以下字符串：

string1 = "1/0/1/A1,A2"
string2 = "1/1/A1,A2"
string3 = "0/A1,A2"

在上面的字符串中，如果字符不存在，我必须将其替换为零。默认结构为“number/number/number/any_character`”，如果缺少任何number，则必须用零替换。答案如下。你知道吗

print(string1) = "1/0/1/A1,A2"
print(string2) = "1/1/0/A1,A2"
print(string3) = "0/0/0/A1,A2"

Answer 1

如果您只想使用字符串操作和循环，请尝试以下操作

strings_list = []
for string in [string1, string2, string3]:     # make list containing all strings
    strings_list.append(string)

new_strings = [] # make list containing the new strings
for string in strings_list:
    if string.count("0/") + string.count("1/") == 3:
        # identify the strings not missing a number
        new_strings.append(string)
    if string.count("0/") + string.count("1/") == 2:
        # identify the strings missing 1 number
        string = string[:4] + "0/" + string[4:]
        new_strings.append(string)
    if string.count("0/") + string.count("1/") == 1:
        # identify the strings missing 2 numbers
        string = string[:2] + "0/" + string[2:]
        new_strings.append(string)
print(new_strings)

这导致['1/0/1/A1,A2', '1/1/0/A1,A2', '0/0/A1,A2']。你知道吗