如何检查一个列表的一部分是否在另一个lis中

Question

假设我有两个列表，比如：

list_of_urls = ['https://en.wikipedia.org/wiki/Barack_Obama', 'https://en.wikipedia.org/wiki/President_of_the_United_States', 'google.com']

list_of_blacklisted_urls = ['wikipedia']

如果黑名单url的任何部分在url列表中，如何返回True？我试过：

for url in list_of_urls:
        if any(URL in URLs for URL in list_of_blacklisted_urls):
                return True

但我敢肯定这是行不通的。你知道吗

Answer 1

你很接近。。。但是any函数的工作方式并不像您想象的那样。必须使用嵌套循环。你知道吗

举个例子：

list_of_urls = ['https://en.wikipedia.org/wiki/Barack_Obama', 'https://en.wikipedia.org/wiki/President_of_the_United_States', 'google.com']

list_of_blacklisted_urls = ['wikipedia']

for url in list_of_urls:
    for keyword in list_of_blacklisted_urls:
        if keyword in url:
            print("FOUND", keyword, "in", url)