我的任务是创建一个程序,打开并读取文本文件,计算成绩(包括平均权重),给出最终成绩,将其更改为字母成绩,然后将其写入新的文本文件。在分数转换成字母分数之前,一切都很顺利。所有的分数都在70-89之间,所以我没有费心为A、B或E(F)设置任何其他代码。每当我试图把成绩转换成字母成绩时,每个人的成绩都会变成C。我哪里出错了?你知道吗
infile = open("c:\\Python34\\MyFiles\\ClassGradebook.txt","r")
outfile = open("c:\\Python34\\myfiles\\ClassGrades.txt","w")
aline = infile.readline() # uses readline method to read the first line of the file
def quizsum():
quizsum1 = quiz1 + quiz2 + quiz3
quizavg = (quizsum1 / 30) * .3
return float(quizavg)
def midtermsum():
midtermsum1 = midterm1 + midterm2
midtermavg = (midtermsum1 / 200) * .4
return float(midtermavg)
def finalsum():
finalsum1 = final1
finalavg = (finalsum1 / 100) * .3
return float(finalavg)
def lettergrade():
if printedgrade >= 70 <= 79:
return "C"
else:
return "B"
while aline:
items = aline.split()
dataline = items[0] + " " + items[1]
quiz1 = int(items[2])
quiz2 = int(items[3])
quiz3 = int(items[4])
midterm1 = int(items[5])
midterm2 = int(items[6])
final1 = int(items[7])
quizavg = quizsum()
midtermavg = midtermsum()
finalavg = finalsum()
gradetotal = quizavg + midtermavg + finalavg
printedgrade = gradetotal * 100
printedgrade2 = lettergrade()
print(dataline)
print(printedgrade2)
outfile.write(printedgrade2 + '\n') newline character
aline = infile.readline()
infile.close()
outfile.close()
应该是
你也可以这样做:
因为你的
if
总是在计算true,因为它是无序的。应该是:70 <= printedgrade <= 79
你的陈述总是正确的,因为正如你所说的,所有的分数都是70-89,所以
printedgrade
将大于或等于70,而70小于79,所以它总是True
。你知道吗尽管我强烈建议让你的代码适用于所有年级。你不能假设,因为这一次成绩总是在一定范围内。你知道吗
相关问题 更多 >
编程相关推荐