Python映射dicts

Question

假设我有几个月的短名字和一些数据

data_in = {"Jan":2.0, "Feb":5.5} 

以及一些包含映射的dict

month_names = {"Jan":"January", "Feb":"February"}
day_month = {day:"Jan" for day in range(1,32)}
day_month.update({day:"Feb" for day in range(32,60)})

如何获得包含长名称和元组形式的日数的原始数据的dict？你知道吗

{("January", 1):2.0, ("January", 2):2.0 ...}

Answer 1

似乎您要做的是迭代day_month字典的键，并为每个键取month_names和data_in中的值的匹配项，因此它应该如下所示：

result = {}
for day in day_month.keys():
    short_month = day_month[day]
    data = data_in[short_month]
    name = month_names[short_month]
    new_key = (name, day)
    result[new_key] = data

Answer 2

这是我自己的尝试-

from itertools import count
c = count(1,1)
days = {"Feb" : 28, "Jan" : 31}

mapping = {(month_names[i], next(c)) : data_in[i]  for i in data_in.keys()  for _ in range(days[i])}

print (mapping)

或使用您的day_monthdict

mapping = {(month_names[day_month[i]], i) : data_in[day_month[i]] for i in day_month.keys()} 

print mapping 

输出-

{('January', 1): 2.0,
 ('January', 2): 2.0,
 ('January', 3): 2.0,
 ('January', 4): 2.0,
 ('January', 5): 2.0,
 ('January', 6): 2.0,
 ('January', 7): 2.0,
 ('January', 8): 2.0,
 ('January', 9): 2.0,
 ('January', 10): 2.0,
 ('January', 11): 2.0,
 ('January', 12): 2.0,
 ('January', 13): 2.0,
 ('January', 14): 2.0,
 ('January', 15): 2.0,
 ('January', 16): 2.0,
 ('January', 17): 2.0,
 ('January', 18): 2.0,
 ('January', 19): 2.0,
 ('January', 20): 2.0,
 ('January', 21): 2.0,
 ('January', 22): 2.0,
 ('January', 23): 2.0,
 ('January', 24): 2.0,
  ..... }