将.csv表转换为字典

2024-05-13 03:33:22 发布

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所以我有几个csv文件,格式如下:

person,age,nationality,language
Jack,18,Canadian,English
Rahul,25,Indian,Hindi
Mark,50,American,English
Kyou, 21, Japanese, English

我需要导入它,并将该数据作为字典返回,其中键作为第一行的列标题,每列中的所有数据作为该特定键的值。例如:

dict = {
    'person': ['Jack', 'Rahul', 'Mark', 'Kyou'],
    'age': [18, 25, 50, 21],
    'nationality': ['Canadian', 'Indian', 'American', 'Japanese'],
    'language': ['English', 'Hindi', 'English', 'English']
}

你知道我该如何开始这段代码,并使它能够为.csv文件中给定的任意数量的列工作吗?


Tags: 文件csvageenglishlanguagepersonindianmark
3条回答

我喜欢这样:

import csv

with open('input') as fin:
    csvin = csv.reader(fin)
    header = next(csvin, [])
    print dict(zip(header, zip(*csvin)))

# {'person': ('Jack', 'Rahul', 'Mark', 'Kyou'), 'age': ('18', '25', '50', ' 21'), 'language': ('English', 'Hindi', 'English', ' English'), 'nationality': ('Canadian', 'Indian', 'American', ' Japanese')}

相应地适应。

这里有一个相当简单的解决方案,它使用python CSV模块(这里的文档:http://docs.python.org/2/library/csv.html)。只需将“csv_data.csv”替换为您的csv文件名。

import csv

with open('csv_data.csv') as csv_data:
    reader = csv.reader(csv_data)

    # eliminate blank rows if they exist
    rows = [row for row in reader if row]
    headings = rows[0] # get headings

    person_info = {}
    for row in rows[1:]:
        # append the dataitem to the end of the dictionary entry
        # set the default value of [] if this key has not been seen
        for col_header, data_column in zip(headings, row):
            person_info.setdefault(col_header, []).append(data_column)

    print person_info

使用csv模块,我可以这样做:

with open('somefile.csv', 'rb') as input_file:
    reader = csv.DictReader(input_file)
    results = {}
    for linedict in reader:
        for (key, value) in linedict.iteritems():
            results.setdefault(key, []).append(value)

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