Crontab以特定间隔获取脚本列表

Question

我们如何使用python crontab获得在特定时间（比如下午4:00到8:00）之间crontab中运行的脚本列表 我正在获取该用户在crontab中运行的所有作业的列表，但无法在特定时间获取。你知道吗

这样尝试：

正在获取所有脚本的列表。你知道吗

from crontab import CronTab
import datetime
import croniter

cron = CronTab("user")

for j in cron:
   print j

在特定的时间之间尝试：

from crontab import CronTab
import datetime
import croniter

cron = CronTab("pfmuser")

for j in cron:
    hour = int(j.split()[1])
    minutes = int(j.split()[0])
    if hour >= 16 and hour <= 20:
        print('fond a job running between 16 and 20')

得到错误：AttributeError：'CronItem'对象没有属性'split'

错误已完成，但

***but now i have:
1) 10 0 * * 5
2)  0 3 1 * *
3)  0 0 * * *
4)  0 1 * * *
5)  0 10 * * * 

now if have some problem and the cron scripts didnt run then if i am running for 0-10th hour then i need only 

3)  0 0 * * *
4)  0 1 * * *
5)  0 10 * * *  
these scripts only should run 

1) 10 0 * * 5  (only friday)
2)  0 3 1 * * (only 1st month)
these should not run 

how to  keep  this may be can i use datetime and get that particular details later compare with the cron info.How do i go*** 

编辑脚本，建议如下：

from crontab import CronTab
import datetime
from croniter import croniter as ci

cron = CronTab("pfmuser")

for cronitem in cron:

    cronitemstr = str(cronitem)
    hour = cronitemstr.split()[1]
    minutes = cronitemstr.split()[0]
    minutesint = None
    hourint = None
    try:
        hourint = int(hour)
        minutesint = int(minutes)
    except ValueError as e:
        print e.message
    if hourint >= 16 and hourint <= 20:
        cronitemstr = cronitemstr[:cronitemstr.index(cronitemstr.split()[5])]

        min=cronitemstr.split()[0]
        dom=cronitemstr.split()[2]
        mon=cronitemstr.split()[3]
        dow=cronitemstr.split()[4]
       date_time=datetime.datetime.now()
        try:
           if(min=='*' and dom=='*' and mon=='*' and dow=='*' ):
                print cronitemstr
                print cronitem
           else:
                print "none"
        except Exception as e:
            print "e"

需要在if子句中包含更多的条件，因为我们需要包含偶数

• 16**3:dis是根据今天星期四的16小时，它需要工作，所以这个脚本也应该显示出来
• 16**1-5：表示周一、周二、周三、周四、周五应运行，因此也应显示。你知道吗
• 16*10*：表示在第10个月的第16个小时内，它需要执行的每一天。所以也应该显示 像这样我们需要检查很多情况。据我所知，我认为我需要考虑今天的约会datetime.date.today日期（）从此需要与h cron表达式进行比较。 prsently*16***是指每分钟16小时的所有脚本，这个月。这个月只有一个实例cce需要考虑所有需要包含的实例

Answer 1

cronitem对象不是字符串，因此没有属性split。在你尝试分裂之前，你可以把它转换成str。例如：

from crontab import CronTab
import datetime
from croniter import croniter as ci

cron = CronTab("pfmuser")



for cronitem in cron:

    cronitemstr = str(cronitem)
    hour = cronitemstr.split()[1]
    minutes = cronitemstr.split()[0]
    minutesint = None
    hourint = None
    try:
        hourint = int(hour)
        minutesint = int(minutes)
    except ValueError as e:
        print e.message

    print hourint
    print minutesint
    if hourint >= 16 and minutesint <= 20:
        print('found a job running between 16 and 20')

        cronitemstr = cronitemstr[:cronitemstr.index(cronitemstr.split()[5])]
        iter = ci(cronitemstr)
        next_run = iter.get_next()
        last_run = iter.get_prev()
        next_run_datetime = datetime.datetime.fromtimestamp(next_run)
        last_run_datetime= datetime.datetime.fromtimestamp(last_run)
        print 'the next run is at {}'.format(next_run_datetime)
        print 'the last run was at {}'.format(last_run_datetime)