2024-04-20 04:44:45 发布
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有一种方法:
>>> px0, px1 = np.where(0==a[:,:,3]%3) >>> a[px0, px1, :3] = 0 >>> a array([[[ 0, 0, 0, 3], [ 4, 5, 6, 7]], [[ 8, 9, 10, 11], [ 0, 0, 0, 15]], [[16, 17, 18, 19], [20, 21, 22, 23]]])
或者
>>> px = np.where(0==a[:,:,3]%3) >>> a[..., :3][px] = 0 >>> a array([[[ 0, 0, 0, 3], [ 4, 5, 6, 7]], [[ 8, 9, 10, 11], [ 0, 0, 0, 15]], [[16, 17, 18, 19], [20, 21, 22, 23]]])
>>> a[(*px, np.s_[:3])] = 0 >>> a array([[[ 0, 0, 0, 3], [ 4, 5, 6, 7]], [[ 8, 9, 10, 11], [ 0, 0, 0, 15]], [[16, 17, 18, 19], [20, 21, 22, 23]]])
有一种方法:
或者
或者
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