ValueError:基为10的int（）的文本无效：“0.50”（我无法理解有关此的其他帖子）

Question

我不能输入小数点，因为它出现了这个错误

我试过把“float”函数放在不同的地方

def Change():
  Money = int(input("How Much Money Do You Want To Change For Cash? - "))
  CoinType = int(input("What Type Of Coin Do You Want To Change Into? (1.00, 0.50, 0.20, 0.10, 0.05, 0.02, 0.01) - "))
  float(CoinType)
  if CoinType == 1:
    print("You Will Get", Money / CoinType,"Coins")
  if CoinType == 0.50:
    print("You Will Get", Money / CoinType,"Coins")

它应该有“你会得到”，货币/硬币类型，“硬币”

Answer 1

用float代替int。整数（int）不能容纳任何十进制数

Answer 2

您需要int输入，而您指示用户在以下行中传递float值：

CoinType = int(input("What Type Of Coin Do You Want To Change Into? (1.00, 0.50, 0.20, 0.10, 0.05, 0.02, 0.01) - "))

因此，将其更改为float应该可以解决问题：

CoinType = float(input("What Type Of Coin Do You Want To Change Into? (1.00, 0.50, 0.20, 0.10, 0.05, 0.02, 0.01) - "))

Answer 3

你应该使用float

CoinType = float(input("What Type Of Coin Do You Want To Change Into? (1.00, 0.50, 0.20, 0.10, 0.05, 0.02, 0.01) - "))