如何在python中将一个列表插入到另一个列表中

Question

这是我的密码：

d = ['ant', 'bird', 'gecko', 'snake', 'wasp']
a = ['rabbit panda bird rabbit', 'bird gecko ant panda', 'wasp snake gecko ant']
b = []
for i in range (0, len(a)):
    c = a[i].split()
    for i in d:
        b.append(c.count(i))
print(b)

输出如下：

[0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1, 0, 1, 1, 1]

但我想要这样的期望输出：

[[0, 1, 0, 0, 0], [1, 1, 1, 0, 0], [1, 0, 1, 1, 1]]

Answer 1

我认为这达到了你想要的：

d = ['ant', 'bird', 'gecko', 'snake', 'wasp']
a = ['rabbit panda bird rabbit', 'bird gecko ant panda', 'wasp snake gecko ant']
b = []
for i in range (0, len(a)):
    c = a[i].split()
    e = []
    for i in d:
        e.append(c.count(i))
    b.append(e)
print(b)

请注意，添加了一个本地数组“e”，其中包含附加的内容，然后将其附加到数组“b”中

Answer 2

使用列表理解：

d = ['ant', 'bird', 'gecko', 'snake', 'wasp']
a = ['rabbit panda bird rabbit', 'bird gecko ant panda', 'wasp snake gecko ant']

list_of_lists = [[x.split().count(y) for y in d] for x in a]

print list_of_lists

输出：

[[0, 1, 0, 0, 0], [1, 1, 1, 0, 0], [1, 0, 1, 1, 1]]

Answer 3

使用python的列表理解

d = ['ant', 'bird', 'gecko', 'snake', 'wasp']
a = ['rabbit panda bird rabbit', 'bird gecko ant panda', 'wasp snake gecko ant']
b = []
for i in range (0, len(a)):
    c = a[i].split()
    b.append([c.count(i) for i in d])
print(b) # [[0, 1, 0, 0, 0], [1, 1, 1, 0, 0], [1, 0, 1, 1, 1]]