Python:我在范围鳟鱼

2024-03-28 11:49:38 发布

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这是我的密码:

 for i in range(self.inputCount, len(self.neurons)):
        currNode=self.neurons[i]
        for k in range(len(currNode.inNeuron)):
            print 'len(currNode.inNeuron) =', len(currNode.inNeuron)
            print 'range(len(currNode.inNeuron)) =', range(len(currNode.inNeuron))
            print 'k =', k
            if currNode.inNeuron[k] == editNode:
                currNode.inNeuron.pop(k)

因为某种原因每当我运行这个和len(currNode.inNeuron公司)为1,范围为[0],k为1。在这种情况下,我只希望k为零。这是打印输出的示例

range(len(currNode.inNeuron)) = [0]
k = 0
len(currNode.inNeuron) = 1
range(len(currNode.inNeuron)) = [0]
k = 0
len(currNode.inNeuron) = 2
range(len(currNode.inNeuron)) = [0, 1]
k = 0
len(currNode.inNeuron) = 1
range(len(currNode.inNeuron)) = [0]
k = 1
Traceback (most recent call last):
  File "neuralnet.py", line 99, in <module>
    if __name__=="__main__":main()
  File "neuralnet.py", line 95, in main
    net1.randomizeNet(5)
  File "neuralnet.py", line 84, in randomizeNet
    self.eraseNode()
  File "neuralnet.py", line 52, in eraseNode
    if currNode.inNeuron[k] == editNode:

有没有办法解决这个问题?你知道吗


Tags: inpyselfforlenifmainline
1条回答
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1楼 · 发布于 2024-03-28 11:49:38

也许可以试试这个

 for i in range(self.inputCount, len(self.neurons)):
    currNode=self.neurons[i]
    for k in range(len(currNode.inNeuron)):
        print 'len(currNode.inNeuron) =', len(currNode.inNeuron)
        print 'range(len(currNode.inNeuron)) =', range(len(currNode.inNeuron))
        if( len(currNode.inNeuron == 1 && range(len(currNode.inNeuron == 0)) )
            print 'k = 0'
        else
            print 'k =', k
        if currNode.inNeuron[k] == editNode:
            currNode.inNeuron.pop(k)

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