我是一个完整的初学者与Python所以请容忍我。你知道吗
我有一个目录,看起来像:
list = [
{
"name": "Bus 60",
"direction": "City",
"timeLeft": "1",
"timeNext": ""
},
{
"name": "Bus 60",
"direction": "City",
"timeLeft": "3",
"timeNext": ""
},
{
"name": "Bus 1",
"direction": "Some Place",
"timeLeft": "15",
"timeNext": ""
},
{
"name": "Bus 1",
"direction": "Some Place",
"timeLeft": "30",
"timeNext": ""
},
{
"name": "Bus 1",
"direction": "That other place",
"timeLeft": "5",
"timeNext": ""
},
]
我希望根据“名称”和“方向”将这两个合并为:
new_list = [
{
"name": "Bus 60",
"direction": "City",
"timeLeft": "1",
"timeNext": "3"
},
{
"name": "Bus 1",
"direction": "Some Place",
"timeLeft": "15",
"timeNext": "30"
},
{
"name": "Bus 1",
"direction": "That other place",
"timeLeft": "5",
"timeNext": ""
},
]
我如何才能做到这一点,也明白它实际上是如何工作的? 我尝试过很多循环的解决方案,但最终都会出现很多重复或错误的合并。你知道吗
编辑:每个名称和方向的副本不会超过一个。你知道吗
编辑2:这是我的完整方法:
@APP.route('/api/vasttrafik/departures', methods=['POST'])
def get_departures():
""" Departures """
APP.logger.info('get_departures():')
data = request.get_json()
id_number = data['id']
current_date = date.today().strftime('%Y-%m-%d')
current_time = datetime.now().strftime('%H:%M')
# time_span = data['']
access_token = request.headers['access_token']
url = 'https://api.vasttrafik.se/bin/rest.exe/v2/departureBoard?id='\
+ id_number + '&date=' + current_date + '&time=' + current_time +\
'&format=json&timeSpan=90&maxDeparturesPerLine=2&needJourneyDetail=0'
headers = {'Authorization': 'Bearer ' + access_token}
req = requests.get(url, headers=headers)
json = req.json()
departure_board = json['DepartureBoard']
if 'error' in departure_board:
raise NotFoundException('Did not find anything')
departures = departure_board['Departure']
def departures_model(item):
def get_key_value(key):
return item[key] if key in item else ''
is_live = 'rtTime' in item
if is_live:
current_time = get_key_value('rtTime')
current_date = get_key_value('rtDate')
else:
current_time = get_key_value('time')
current_date = get_key_value('date')
direction = get_key_value('direction')
via = ''
if 'via' in direction:
direction, via = direction.split('via')
time_departure = datetime.strptime(current_date + ' ' + current_time, '%Y-%m-%d %H:%M')
time_now = datetime.now()
diff = time_departure - time_now
if time_now >= time_departure:
minutes_left = 0
else:
minutes_left = math.floor(((diff).seconds) / 60)
clock_left = item['rtTime'] if is_live else item['time']
return dict({
'accessibility': get_key_value('accessibility'),
'bgColor': get_key_value('bgColor'),
'clockLeft': clock_left,
'clockNext': '',
'timeLeft': int(minutes_left),
'timeNext': '',
'direction': direction.strip(),
'via': 'via ' + via.strip() if via != '' else via,
'name': get_key_value('name'),
'sname': get_key_value('sname'),
'type': get_key_value('type'),
'time': get_key_value('time'),
'date': get_key_value('date'),
'journeyid': get_key_value('journeyid'),
'track': get_key_value('track'),
'fgColor': get_key_value('fgColor'),
'isLive': is_live,
'night': 'night' in item,
})
mapped_departures = list(map(departures_model, departures))
def key(bus):
return bus["name"], bus["direction"]
def merge_busses(ls):
for (name, direction), busses in groupby(ls, key):
busses = list(busses)
times = [bus["timeLeft"] for bus in busses]
yield {
**busses[0],
"timeLeft": min(times, key=int),
"timeNext": max(times, key=int),
}
merge_departures = list(merge_busses(mapped_departures))
return jsonify({
'departures': merge_departures,
})
编辑3:我刚刚发现为什么维亚坦和帕特里克·阿特纳的解决方案不起作用。只有在事先对公交车列表进行排序的情况下,它们才起作用。所以我猜groupby需要dicts与之相邻。你知道吗
一种方法是按它们的
name
&;direction
对所有总线进行分组。然后合并数据,确保“早”时间在'timeLeft'
,晚”时间在'timeNext'
:Doku:itertools.groupby
输出:
您编辑的示例将导致:
我的解决方案是:我们使用
itertools.groupby
按名称方向组合对总线进行分组,然后生成字典,其中timeLeft
是这些总线中最小的分钟数,timeNext
要么是空字符串(如果我们只看到一条总线),要么是这些总线中最大的分钟数。你知道吗像这样使用:
在您的示例中,这将产生:
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