Python逻辑if和或反向

Question

Level = 4
Name = "Mike"
Form = None
if Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form):

上面的代码正是我想要它做的，但是我不知道如何做相反的事情：

例如

if Level != 5 and Name not in ['James','Chris','Alex'] and (Name not in ['John','Mike'] and Form):

尽我所能接近，但效果不一样。你知道吗

Answer 1

你的问题有点模糊，据我所知应该很简单

if not (Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form)):

另一个简单的方法就是这样做

if Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form):
    pass
else:
    # your code here

Answer 2

把所有东西都用圆括号括起来，一开始就用not怎么样。这样，就不需要反转任何运算符。你知道吗

if not (Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form)):