查找XPath段落（跟随同级？）

Question

我将Selenium与Python 2.7.10一起使用，并希望抓取本页"Description"标题后面的段落：http://etfdb.com/etf/ROBO/

from selenium import webdriver as driver
from selenium.common.exceptions import NoSuchElementException

def scrape(driver, key):
    try:
        find_value = driver.find_element_by_xpath("//span[@class='panel__sub-heading' and . = '%s']/following-sibling::p" % key).text
    except NoSuchElementException:
        print "Not Found"
        return None
    else:
        value = re.search(r"(.+)", find_value).group().encode("utf-8")
        print value
        return value

description = scrape(driver, "Description")

我使用的XPath不正确，因为它不会产生任何结果。找到标题"Description"后面的段落的正确方法是什么？你知道吗

Answer 1

这不是span标记-它是h3：

//h3[@class='panel__sub-heading' and . = '%s']/following-sibling::p