二维二进制字符串py

Question

我是pyevolve和Python中的GA新手。
我试图制作一个表示匹配的二维二进制数组。像这样：

  A B C
1 1 0 0
2 0 1 0
3 1 0 0
4 0 0 1

我的目标是每行只有一个“1”，数组中的“1”应该等于行数。一个数字只能与一个字母匹配，但一个字母可以与多个数字匹配。 我在求值函数中编写了这个代码

def eval_func(chromosome):
    score = 0.0
    num_of_rows = chromosome.getHeight()
    num_of_cols = chromosome.getWidth()
    # create 2 lists. One with the sums of each row and one
    # with the sums of each column
    row_sums = [sum(chromosome[i]) for i in xrange(num_of_rows)]
    col_sums = [sum(x) for x in zip(*chromosome)]
    # if the sum of "1"s in a row is > 1 then a number (1,2,3,4) is matched with
    # more than one letter. We want to avoid that.
    for row_sum in row_sums:
        if row_sum <= 1:
            score += 0.5
        else:
            score -= 1.0
    # col_sum is actually the number of "1"s in the array 
    col_sum = sum(col_sums)
    # if all the numbers are matched we increase the score
    if col_sum == num_of_rows:
        score += 0.5
    if score < 0:
        score = 0.0

    return score

似乎可以工作，但当我添加一些其他检查时，例如如果1在A，2不能在C，它就会失败。 这怎么可能呢？（许多支票）

提前谢谢。你知道吗