这个问题我已经解决了好几个小时了。我无法使用规则语法跟踪此站点上的链接,因此我手动找到了发出请求所需的所有链接。即使我测试了提取的链接是有效的url,我的爬虫程序也不会对其他页面进行爬网。我已经被困在这几个小时了。我也没有发现关于Scrapy的文档有那么大的帮助,因为它是用一个完美的单词卡片呈现的。有人能帮忙吗?你知道吗
# -*- coding: utf-8 -*-
import scrapy
import logging
from scrapy.spiders import CrawlSpider, Rule
from scrapy.linkextractors import LinkExtractor
from scrapy import Request
from banker.items import BarclaysOfferItem
class BarclaySpider(CrawlSpider):
name = "barclay"
allowed_domains = ['partners.barclaycardrewardsboost.com/']
start_urls = [
'https://partners.barclaycardrewardsboost.com/shopping/sp____.htm?rows=25&page=1&ref_page_id=2167&ref_section_id=9720&ref_section_title=All%\20Online%\20Offers'
# 'https://partners.barclaycardrewardsboost.com/shopping/sp____.htm?rows=25&page=2&ref_page_id=2167&ref_section_id=9720&ref_section_title=All%\20Online%\20Offers'
# 'https://partners.barclaycardrewardsboost.com/shopping/sp____.htm?rows=25&page=3&ref_page_id=2167&ref_section_id=9720&ref_section_title=All%\20Online%\20Offers',
# 'https://partners.barclaycardrewardsboost.com/shopping/sp____.htm?rows=25&page=4&ref_page_id=2167&ref_section_id=9720&ref_section_title=All%\20Online%\20Offers',
# 'https://partners.barclaycardrewardsboost.com/shopping/sp____.htm?rows=25&page=5&ref_page_id=2167&ref_section_id=9720&ref_section_title=All%\20Online%\20Offers',
# 'https://partners.barclaycardrewardsboost.com/shopping/sp____.htm?rows=25&page=6&ref_page_id=2167&ref_section_id=9720&ref_section_title=All%\20Online%\20Offers',
# 'https://partners.barclaycardrewardsboost.com/shopping/sp____.htm?rows=25&page=7&ref_page_id=2167&ref_section_id=9720&ref_section_title=All%\20Online%\20Offers'
]
def parse(self, response):
base = 'https://partners.barclaycardrewardsboost.com/shopping/sp____.htm'
links = response.xpath('//p[contains(@class, "mn_pageLinks")]/a')
for sel in links:
url = base + str(sel.xpath('@href').extract()[0])
logging.info(url)
yield scrapy.Request(url, callback=self.parse_item)
def parse_item(self, reponse):
for sel in response.xpath('//table/tr'):
item = BarclaysOfferItem()
item['merchant'] = sel.xpath('td/div/a[last()]/text()').extract()
item['rate'] = sel.xpath('td/span/a/text()').extract()
item['offer'] = sel.xpath('td/a[last()]/text()').extract()
item['coupon_code'] = sel.xpath('td[@class="mn_cpCode"]/text()').extract()
item['expiration_date'] = sel.xpath('td[@class="mn_expiry"]/text()').extract()
yield item
更新#1
删除allowed_urls
列表得到了我的工作请求。但是现在我得到了NameError: global name 'response' is not defined
。你知道吗
我终于成功了!你知道吗
根据scrapy documentation,如果启用了offseitemiddleware,则不会为请求读取不在
allowed_domains
列表中的域。我知道我的网址是在指定的域,但我想,网站查询数据的方式使网址似乎是异地的。你知道吗相关问题 更多 >
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