如果循环continue再次执行for循环

Question

if eqp_id:
    for rule in items:
        if rule.eqp_pricelist == True:
            print "id 1"
            print rule.id
            continue
        print "id 2 out"
        print rule.id

#outputs:
#id1
#5
#id 2 out
#4

怎么可能rule.id = 5在rule.id = 4之前

此代码用于方法的产品价格表：

def _price_rule_get_multi(self, cr, uid, pricelist, products_by_qty_by_partner, context=None):

Answer 1

如您在评论中所述，如果items是使用：items = self.pool.get('product.pricelist.item').browse(cr, uid, item_ids, context=context)获得的，那么items是Odoo ORM的“记录集”，因此您可以使用Odoo ORM（see documentation）的sorted()函数：

sorted(key=None, reverse=False) Return the recordset self ordered by key.

Parameters:
key either a function of one argument that returns a comparison key for each record, or None, in which case records are ordered according the default model's order
reverse if True, return the result in reverse order

你知道吗

要将此函数应用于您的代码，请按以下方式进行更改：

if eqp_id:
    for rule in items.sorted(key=lambda r: r.id):  ## sort by id using sort()...
        if rule.eqp_pricelist == True:
            print "id 1"
            print rule.id
            continue
        print "id 2 out"
        print rule.id

你知道吗

编辑：
我看不清楚你的目标，但也要检查filtered()它是否能帮助你：

if eqp_id:
    for rule in items.sorted(key=lambda r: r.id).filtered(lambda r: r.eqp_pricelist == True):  ## sort by id using sort() AND filtered using eqp_pricelist == True...
        print "[True?] Rule with eqp_pricelist == %s" % rule.eqp_pricelist
        print rule.id

或：

if eqp_id:
    for rule in items.sorted(key=lambda r: r.id).filtered(lambda r: r.eqp_pricelist == Talse):  ## sort by id using sort() AND filtered using eqp_pricelist == False...
        print "[False?] Rule with eqp_pricelist == %s" % rule.eqp_pricelist
        print rule.id

也可以只应用filtered()而不应用sorted()。你知道吗

看看这个：for rule in items.filtered("eqp_pricelist"):