循环似乎从来没有真正的循环

Question

print("Welcome to my dice game.")
print("First enter how many sides you would like your dice to have, 4, 6 or 12")
print("Then this program will randomly roll the dice and show a number")
#Introduction explaing what the game will do. Test 1 to see if it worked.
while True:
    #starts a while loop so the user can roll the dice as many times as they find necessary
    import random
    #Imports the random function so the code will be able to randomly select a number
    dice = int(input("Enter which dice you would to use,4, 6, or 12? "))
    #set a variable for the amount of dice number
    if dice == 12:
        x = random.randint(1,12)
        print("You picked a 12 sided dice. You rolled a " + str(x) + " well done")
        #Test 2 see if it does pick a random number for a 12 sided di
    elif dice == 6:
        x = random.randint(1,6)
        print("You picked a 6 sided dice. You rolled a " + str(x) + " well done")
        #Test 3 see if it does pick a random number for a 6 sided di
    elif dice == 4:
        x = random.randint(1,4)
        print("You picked a 4 sided dice. You rolled a " + str(x) + " well done")
        #Test 4 see if it does pick a random number for a 4 sided di
    else:
        print("Sorry, pick either 12, 6 or 4")
        #Test 5 tells the user that they can only pick 4, 6 or 12 if anything else is entered this error shows
    rollAgain = input ("Roll Again? ")
    if rollAgain == "no":
            rollAgain = False
    if rollAgain == "yes":
        rollAgain = True
        break
print ("Thank you for playing")
#if the user enters anything apart from yes y or Yes. The code ends here.

这就是我目前掌握的密码。然而，代码永远不会真正进入循环的开始，无论我输入什么，代码只是显示“谢谢玩”和结束。谁能告诉我哪里出错了吗？你知道吗

Answer 1

问题是，当用户想再次掷骰子时，你打破了循环。当玩家不想再玩时，循环应该会中断，所以你必须：

http://pastebin.com/hzC1UwDM

Answer 2

首先，您应该使用原始输入来获取用户的选择。（假设Python2）如果您使用的是Python3，那么输入就可以了，请继续阅读。你知道吗

不管怎样，当你键入yes时，它仍然会退出，因为你跳出了循环！你应该把break语句移到“no”的情况下，这样当你说你不想再滚动时它就会爆发。你知道吗

rollAgain = raw_input ("Roll Again? ")
if rollAgain == "no":
    break

您根本不需要将rollAgain设置为true或false。在上面的代码中，除了“no”之外的任何东西都被假定为“yes”，但是您可以很容易地添加检查。你知道吗