清除pygame曲面中光标所在的部分

Question

我有一个“你有一个高分，输入你的缩写”屏幕为我的游戏，它的作品。然后我决定我想要一个闪烁的光标，光标应该在首字母所在的位置，它将从首字母开始（x，y），然后当输入时，移到首字母2（x，y）。问题是，如果你按下一个字母时，光标已经绘制了蓝色矩形，它留在屏幕上，我需要清除只是该地区。有办法吗？这是我的初始输入代码和光标闪烁代码：

def update_highscores(index):

    background.fill(BLACK)

    # co-ords for inital entry

    ix = []

    ix1 = (background.get_width()/2) - 25
    ix2 = ix1 + 20
    ix3 = ix2 + 20

    ix.append(ix1)
    ix.append(ix2)
    ix.append(ix3)

    iy= 140

    inits = []
    initsurf = []

    title = "You have a high score"
    textsurface = write(title)
    background.blit(textsurface, ( (background.get_width()/2) - (textsurface.get_width()/2), 60))

    enterinits = "enter your initials"
    textsurface = write(enterinits)
    background.blit(textsurface, ( (background.get_width()/2) - (textsurface.get_width()/2), 90))

    screen.blit(background, (0, 0))
    pygame.display.flip()

    for c in range(3):
        letter = -1
        while letter == -1:
            blink_cursor(ix[c], iy)
            screen.blit(background, (0, 0))
            pygame.display.flip()
            clock.tick(25)

            letter = getkey()   
            screen.blit(background, (0, 0))
            pygame.display.flip()

        if letter <= 127:
            inits. append(chr(letter))

        elif inkey == K_RETURN:
            break

        initsurf.append(write(inits[c]))
        background.blit(initsurf[c], (ix[c], iy))
        screen.blit(background, (0, 0))
        pygame.display.flip()

    initStr = inits[0] + inits[1] + inits[2]
    highnames[index] = initStr

def blink_cursor(x,y):
    global highcursor
    highcursor +=1
    highcursor = highcursor%11

    if highcursor == 5:
        pygame.draw.rect(background, BLUE, (x, y, 20, 20), 0)
    elif highcursor == 10:
        pygame.draw.rect(background, BLACK, (x, y, 20, 20), 0)

Answer 1

快速而肮脏：只需将highcursor设置为9并调用blink\u cursor：

if letter <= 127:
        inits.append(chr(letter).upper())
        highcursor = 9
        blink_cursor(ix[c], iy)
        screen.blit(background, (0, 0))
        pygame.display.flip()

当光标先递增1到10时，当计数为10时，它会绘制一个黑色矩形。已排序。你知道吗