当某个条件为Tru时，用python中的另一个字符串替换列表中的字符串元素

Question

所以我在网上做一个python课程，在那里我得到了一个任务来做一个tic-tac-toe游戏。我做了所有的事情，但是当占位符被用户选择的块中的O或X替换时，我被列表元素的替换卡住了。我已经尝试了很多方法来永久性地替换列表元素，并且花了几个小时来找到正确运行它的方法，但是它仍然打印相同的tic-tac-toe原始板。你知道吗

    # 2 players should be able to play the game (both sitting at the same computer)
# The board should be printed out every time a player makes a move
# You should be able to accept input of the player position and then place a symbol on the board
#          x1 |  y1  |  z1
#        ---- | ---- | ----
#          x2 |  y2  |  z2
#        ---- | ---- | ----
#          x3 |  y3  |  z3
x1= 'top-left'
y1= 'top-mid'
z1= 'top-right'
x2= 'mid-left'
y2= 'mid-mid'
z2= 'mid-right'
x3= 'btm-left'
y3= 'btm-mid'
z3= 'btm-right'
e = [x1,y1,z1,x2,y2,z2,x3,y3,z3]
board = e[0]+ ' | '+ e[1]+ ' | '+ e[2]+'\n'+ \
       '--------|------------|--------'+'\n'+\
        e[3]+ ' | '+ e[4]+ ' | '+ e[5]+'\n'+ \
       '--------|------------|--------'+'\n'+\
        e[6]+ ' | '+ e[7]+ ' | '+ e[8]


def instructions():
    print('Instuctions: \n')
    print('Game: tic-tac-toe \n')
    print('Player 1: O and Player 2: X \n\n')
    print(' top-left | top-mid | top-right')
    print(' -------- | ------- | ----------')
    print(' mid-left | mid-mid | mid-right')
    print(' -------- | ------- | ----------')
    print(' btm-left | btm-mid | btm-right')
    print('\n\n')
    print('Choose your input when your turn comes.\n\n')


def player_one(inputvalue):
    global e
    for element in e:
        if element == inputvalue:
            e[e.index(element)]='   O    ' #element that i wanna replace
            break
    query =checkSuccess()
    if (query == True):
        print('Tic-Tac-Toe ! Player1 has won the game! ')
    elif (query == False):
        print(board)    # this still prints the original, old board.


def player_two(input):
    global e
    for element in e:
        if element== input:
            e[e.index(element)] ='   X    '
            break
    query =checkSuccess()
    if (query == True):
        print('Tic-Tac-Toe ! Player2 has won the game! ')
    elif (query == False):
        print(board)
        ticTacToe()

board = e[0]+ ' | '+ e[1]+ ' | '+ e[2]+'\n'+ \
        e[3]+ ' | '+ e[4]+ ' | '+ e[5]+'\n'+ \
        e[6]+ ' | '+ e[7]+ ' | '+ e[8]

def checkSuccess():
    if(e[0]==e[1]==e[2] or e[3]==e[4]==e[5] or e[6]==e[7]==e[8] or e[0] == e[3] == e[6] or
            e[1]==e[4]==e[7] or e[2]==e[5]==e[8] or e[0]==e[4]==e[8] or e[6]==e[4]==e[2]):
        return True
    else:
        return False

def ticTacToe():
    p1 = input("Player1, Enter your choice \n")
    player_one(p1)
    p2 = input("Player2, Enter your choice \n")
    player_two(p2)

instructions()
print(board)
ticTacToe()

我得到的结果是：

top-left | top-mid | top-right
mid-left | mid-mid | mid-right
btm-left | btm-mid | btm-right
Player1, Enter your choice 
mid-mid
top-left | top-mid | top-right
mid-left | mid-mid | mid-right
btm-left | btm-mid | btm-right
Player2, Enter your choice 
btm-right
top-left | top-mid | top-right
mid-left | mid-mid | mid-right
btm-left | btm-mid | btm-right
Player1, Enter your choice 

o/p仍然是一样的。是否有方法替换元素并打印列表的新值？你知道吗

Answer 1

Board变量只定义一次。它是一个字符串，它是不可变的，当您更改e列表的元素时，它不会神奇地更新。正如Danilo在他的answer中所建议的，您可以创建一个函数，并在每次需要打印电路板时调用它：

from beautifultable import BeautifulTable

def draw_board():
    board = BeautifulTable()
    board.append_row(e[:3])
    board.append_row(e[3:6])
    board.append_row(e[6:])
    print(board)

您可以使用^{}格式化您的电路板。但是，您需要先安装它：

pip install beautifultable

示例：

>>> e[0] = 'X'
>>> draw_board()
+     +    -+     -+
|    X     | top-mid | top-right |
+     +    -+     -+
| mid-left | mid-mid | mid-right |
+     +    -+     -+
| btm-left | btm-mid | btm-right |
+     +    -+     -+