from collections import defaultdict
l = [('a',1),('b',2),('a',3)]
d = defaultdict(list)
for pair in l:
d[pair[0]].append(pair[1]) #add each number in to the list with under the correct key
for (k,v) in d.items():
d[k] = sum(d[k])/len(d[k]) #re-assign the value associated with key k as the sum of the elements in the list divided by its length
from collections import defaultdict
l = [('a',1),('b',2),('a',3)]
temp_d = defaultdict(list)
for pair in l:
temp_d[pair[0]].append(pair[1])
#CHANGES HERE
final = dict((k,sum(v)/len(v)) for k,v in temp_d.items())
print(final)
>>>
{'a': 2, 'b': 2}
所以呢
或者更好,最后制作一本简单的字典:
请注意,如果您使用的是2.x(现在,您需要调整以下内容以强制浮点除法):
或者
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